What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m? (Please sh
1 answer:
We have been given the measure of two parallel sides as 11 m and 5 m. And we are given one of the slanted sides as 4 m.
From the given information, we can find the base of one of the side triangles as 3 m.
Therefore, upon using Pythagorean theorem, we get the set up for height as
Therefore, height of the required figure is m
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Answer:
The graph is uploaded in the attachment.
The value of x is 2.625.
Step-by-step explanation:
- let us plot f(x), g(x) on y-axis
so, f(x)=y and g(x)=y.
- the first equation can be written as y=5-2x
- the general equation of a straight is y=mx+c
( where m is the slope and c is the y-intercept )
- now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
- the slope of second equation i.e, y=(2/3)x-2 is 2/3 and its y-intercept is -2.
- now plot the graph using above information.
(y-intercept is the the coordinate of a point where the line intersects y-axis)
(slope is the angle made by the line with the x-axis)
- by seeing the graph, the value of x is 2.625.
