9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Y=a(x-h)^2+k
-5=a(1-0)^2+2
-5=a+2
-3=a
y=-3x^2+2
Answer:
The answer is C
Step-by-step explanation:
It starts at 25 and then it stops at 38.
I hope this helps!
Answer:
1,000 ft³
Step-by-step explanation:
The volume is given by ...
V = Bh
where B is the area of the base, and h is the height. For the given dimensions, the volume is ...
V = (200 ft²)(5 ft) = 1000 ft³