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kolbaska11 [484]
4 years ago
6

Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2

Mathematics
1 answer:
Crank4 years ago
8 0
<h3>I'll teach you how to factor 6x^2y − 3xy − 24xy^2 + 12y^2</h3>

---------------------------------------------------------------------

6x^2y − 3xy − 24xy^2 + 12y^2

Apply exponent rule:

6x^2y-3xy-24xyy+12yy

Rewrite 12 as 4*3

Rewrite -24 as 8*3

Rewrite 6 as 2*3

2*3x^2y-3xy+8*3xyy+4*3yy

Factor out common term 3y:

3y(2x^2-x-8xy+4y)

Factor 2x^2-x-8xy+4y:

3y(2x-1)(x-4y)

Your Answer Is 3y(2x-1)(x-4y)

plz mark me as brainliest if this helped :)

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Recall the sum identity for cosine:

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Since both a and b terminate in the first quadrant, we know that both cos(a) and sin(b) are positive. Then using the Pythagorean identity,

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