All of them are 3.14
I got them all right on I ready :)))
In ΔJKL
s = JK+KL+LJ/2
= 25+7+21/2
= 28
then,
ΔJKL = √[s(s-a)(s-b)(s-c)]
= √[28(28-25)(28-24)(28-7)
= √(28×3×4×21)
= √(7056
= 84cm²
Again,
ΔJKL = 1/2×JL×LK×∠L
or, 84 = 1/2×24×7×sin x°
or, 84/168 = sin x°
or, 1/2 = sin x°
or sin 30° = sin x°
or x° = 30°
At last,
∠K+∠L+∠J = 180° (sum of angle of triangle)
or, ∠K+30°+90° = 180°
or, ∠K = 180°- 120°
or, ∠K = 60°
