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brilliants [131]
3 years ago
11

Which is more precise 5 kg or 5212 g

Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0
5 kg is more precise because if you said 5212 g, they will be trying to see what the precise answer is so if you say 5 kg that will save all of the work. 

P.S.: its not 5212 g, its 5000 g. :)
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PIT_PIT [208]

Answer:

3. r = -8

4. x = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

2(-5r + 2) = 84

<u>Step 2: Solve for </u><em><u>r</u></em>

  1. Divide 2 on both sides:                    -5r + 2 = 42
  2. Subtract 2 on both sides:                 -5r = 40
  3. Divide -5 on both sides:                    r = -8

<u>Step 3: Check</u>

<em>Plug in r into the original equation to verify it's a solution.</em>

  1. Substitute in <em>r</em>:                   2(-5(-8) + 2) = 84
  2. Multiply:                             2(40 + 2) = 84
  3. Add:                                   2(42) = 84
  4. Multiply:                             84 = 84

Here we see that 84 does indeed equal 84.

∴ r = -8 is a solution of the equation.

<u>Step 4: Define equation</u>

264 = -8(-8 + 5x)

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Divide both sides by -8:                    -33 = -8 + 5x
  2. Add 8 to both sides:                          -25 = 5x
  3. Divide 5 on both sides:                      -5 = x
  4. Rewrite:                                               x = -5

<u>Step 6: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in<em> x</em>:                    264 = -8(-8 + 5(-5))
  2. Multiply:                               264 = -8(-8 - 25)
  3. Subtract:                              264 = -8(-33)
  4. Multiply:                               264 = 264

Here we see that 264 does indeed equal 264.

∴ x = -5 is a solution of the equation.

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