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Shkiper50 [21]
3 years ago
6

An inelastic collision occurs in one dimension, in which a 10 kg block traveling at 5 m/s collides with a 5 kg block traveling a

t 3 m/s in the same direction, and they stick together. What are the velocities of the blocks immediately after the collision?
Physics
1 answer:
gulaghasi [49]3 years ago
7 0
Why’d Kahn’s his Judd hue
us jibe Japheth JSU’s
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Two mountain bikers are rolling down a hill. They both have the same mass, but one is taller and has more air drag (friction, et
svetlana [45]

Answer:The Taller one

Explanation: Air drag(friction) also known as air resistance,the opposing force acting against the force of gravity, if a falling Object have a high air drag it will mean the object have a high air resistance. The higher the air resistance the higher the impact of the force of gravity on an object. The force of gravity will act to want to overcome the opposing force in order to bring the Object or the taller person down.

4 0
4 years ago
What is the distance of a car travels is its velocity is 30 mph and its time is 2 hours ?
Alborosie

Answer:

distance = 60 miles

Explanation:

3 0
2 years ago
The rod of the fixed hydraulic cylinder is moving to the left with a constant speed vA = 25 mm/s. Determine the corresponding ve
Montano1993 [528]

Explanation:

let vertical distance from A to C be  h=250mm the constraint equation is:

l_{ac} +l_{ab} =L

we want to find l_{bc} distance can be written as l_{bc} =h_{1}+h_{2} which we will find by using Pythagorean theorem h 1 is a constant and can be written as h:

h_{2} =\sqrt{l_{ab}^2- s_{A} ^2}

l_{ac} =\sqrt{s_{A}^2+ h^2 }

l_{ab} =L-\sqrt{s_{A} ^2+h^2 }

taking derivative w.r.t time we get

h^._{2} =-v_{B =(l_{ab} l_{ab} ^.-s_{A} v_{A} )/h_{2}

l_{ab} ^.=(s_{A} v_{A} )/l_{ab} -L

given s_{A} =425mm which gives us

l_{ab} =1050-\sqrt{450^2+250^2} =556.923mm\\\\h_{2} =\sqrt{556.923^2-425^2}=359.914mm

l_{ab} ^.=(425.25)/(556.923-1050)=-21.548mm\\\\-v_{B} =(-556.923*21.548-425.25)/(359.914)\\\\v_{B} =62.864mm/s

5 0
4 years ago
How do you make magnetic and static forces strong or week?
victus00 [196]
You make them strong for example if you rub a balloon in your hair the longer you do it the longer it sticks because of static
6 0
3 years ago
A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it atta
Jobisdone [24]

Answer: The correct answer is option b.

Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.

The acceleration of the rocket is 99.0m/s^2

To calculate the distance of rocket, we use third equation of motion, which is:

v^2-u^2=2as

where, v = final velocity = 445m/s

u = initial velocity = 0m/s

a = acceleration = 99m/s^2

s = distance = ? m

Putting values in above equation, we get:

(445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters

3 0
3 years ago
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