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xz_007 [3.2K]
3 years ago
14

Can you help me plss! ​

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

(1/3) × the cone's volume = The cylinder's volume.

Step-by-step explanation:

Step 1:

The volume of any cone is obtained by multiplying \frac{1}{3} with π, the square of the radius (r^{2}) and the height (h).

So the volume of the cone, V=\pi r^{2} \frac{h}{3}.

Step 2:  

The cylinder's volume is nearly the same as the cone but instead by multiplying \frac{1}{3} we multiply with 1.

So the cylinder's volume is determined by multiplying π with the square of the radius of the cylinder (r^{2}) and the height of the cylinder (h).

So the the cone's volume, V = \pi r^{2} h.

Step 3:

Now we equate both the volumes to each other.

The cone's volume : The cylinder's volume = \pi r^{2} \frac{h}{3}: \pi r^{2} h = \frac{1}{3} : 1.

So if we multiply the cone's volume with \frac{1}{3} we will get the cylinder's volume with the same dimensions.

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The recipe for potato salad calls for one teaspoon of vinegar for every 2 teaspoons of mayo how many teaspoons of vinegar are ne
lozanna [386]
To solve this, you see that the amount of mayo is double that of vinegar, so you can simply divide 16/2 to get 8 teaspoons of vinegar
8 0
4 years ago
Please help with this question​
ioda

Answer:

25

Step-by-step explanation:

\frac{5^8 \times 5^{-2}}{5^4}

\frac{5^{8+-2}}{5^4}

\frac{5^{6}}{5^4}

5^{6-4}

5^2

=25

3 0
3 years ago
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
3 years ago
Read 2 more answers
Answer 10,11,12,13,14
QveST [7]
10
13.50 per set
+.45 per day value
she got 20 sets
5 days after would be
13.50 ×20=270
value of 20 sets at 13.50 a set on day one was 270.00
.45×20=9.00
the 20 sets gain 9 dollars a day
9×5=45
9 dollars a day times 5 days is 45 dollars
45+270=315

11
4 0
3 years ago
What is the value of x?
Over [174]

Answer:

c-12

Step-by-step explanation:

Pythagoras theorem states that a²+b²=c²

144+b²=c²

b²=c²-144

b=c-12

b=x

x=c-12

4 0
3 years ago
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