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4 years ago

Which angles are pairs of corresponding angles? Check all that apply

Mathematics

1 answer:

AleksAgata [21]4 years ago

6 0

Answer:

B and D people. Your welcome.

Step-by-step explanation:

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How many solutions does the system have?<br> 3x + 2y = 7<br> y = -3x + 11

ella [17]

Answer:

1 Solution.

Step-by-step

The answer is (5, -4) or x= 5, y= -4 making this system have 1 solution.

If you can please make mine the brainliest that would be much appreciated. Thanks!

6 0

3 years ago

a crew workers paved 2/15 mile in 20 minutes. if they work at the same rate what portion of a mile will they pave in one hour?

ANEK [815]

Since 20 min is 1/3 of a mile 20 min*3=1 hour. then u multiply 2/5 by 3 to get 6/5.

6 0

3 years ago

The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?

VARVARA [1.3K]

Answer:

$\displaystyle - 155$

Step-by-step explanation:

we are given a quadratic function

$\displaystyle f(x) = - 5 {x}^{2} + 30x - 200$

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

$\displaystyle x _{ \rm min} = \frac{ - b}{2a}$

the given function is in the standard form i.e

$\displaystyle f(x) = a {x}^{2} + bx + c$

so we acquire:

b=30
a=-5

thus substitute:

$\displaystyle x _{ \rm min} = \frac{ - 30}{2. - 5}$

simplify multiplication:

$\displaystyle x _{ \rm min} = \frac{ - 30}{ - 10}$

simply division:

$\displaystyle x _{ \rm min} = 3$

plug in the value of minimum x to the given function:

$\displaystyle f (3)= - 5 {(3)}^{2} + 30.3 - 200$

simplify square:

$\displaystyle f (3)= - 5 {(9)}^{} + 30.3 - 200$

simplify multiplication:

$\displaystyle f (3)= - 45 + 90- 200$

simplify:

$\displaystyle f (3)= - 155$

hence,

the minimum value of the function is -155

5 0

3 years ago

Plz help me with this

Anna [14]

Answer:

Step-by-step explanation:

Mmmmmmmm.

8 0

3 years ago

Simplity 15 + 6(x+1)

8090 [49]

Answer:(15x+15)(6x+6)

Step-by-step explanation:

5 0

3 years ago