The ratios would remain the same for both elements, so it would be 1.5 times the mass of sodium in 100 grams.
1.5 * 39.34 grams Na = 59.01 grams Na
Answer: (a) The solubility of CuCl in pure water is .
(b) The solubility of CuCl in 0.1 M NaCl is .
Explanation:
(a) Chemical equation for the given reaction in pure water is as follows.
Initial: 0 0
Change: +x +x
Equilibm: x x
And, equilibrium expression is as follows.
x =
Hence, the solubility of CuCl in pure water is .
(b) When NaCl is 0.1 M,
,
,
Net equation:
= 0.1044
So for,
Initial: 0.1 0
Change: -x +x
Equilibm: 0.1 - x x
Now, the equilibrium expression is as follows.
K' =
0.1044 =
x =
Therefore, the solubility of CuCl in 0.1 M NaCl is .
Answer:
That should be CaCl2. Otherwise, all your mathematics would be for naught.
Explanation:
Answer:
155g
Explanation:
To solve this problem, we have to derive the number of moles of the element given from the number of atoms first.
Number of atoms = 3.01 x 10²⁴ atoms
From mole concept;
6.02 x 10²³ atoms is found in 1 mole of a substance
3.01 x 10²⁴ atoms of P will contain = 5moles of P
Now;
Mass of P = number of moles x molar mass
Molar mass of P = 31g/mol
Mass of P = 5 x 31 = 155g
What biochemical reaction??