The amount of water that will be produced is 50.36 grams
<h3>Stoichiometric problems</h3>
The metabolism of glucose is represented by the following equation:

The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
More on stoichiometric problems can be found here: brainly.com/question/14465605
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To find pH, use the following formula ---> pH= - log [H+]
so first we need to calculate the [H+] concentration using the OH concentration. to do this, we need to use this formula--> 1.0x10-14= [H+] X [OH-], so we solve for H+ and plug in
[H+]= 1.0X10-14/[OH-]---> 1.0 x 10-14/ 1.0 x 10-4= 1.0 x 10-10
now that we have the H+ concentration, we can solve of pH
pH= -log (1.0x10-10)= 10
answer is A
KOH -------> K+ OH-
Ba(OH)2 ------> Ba+2. 2OH-
Answer: this question is 3 days ago? Omg