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Svet_ta [14]
2 years ago
10

During a laboratory experiment 3.81g of NaHCO3 was thermally decomposed to generate 2.86 grams of carbonic acid (H2CO3). Calcula

te the percent yield of carbonic acid for the reaction. Show all work for the calculation (10 points).
NaHCO3 → Na2CO3 + H2CO3
Chemistry
1 answer:
Eva8 [605]2 years ago
4 0

Answer:

H2CO3

Explanation:

tahts hard hope u find the answer :)

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The mass of a silver bracelet is 2.5 gram, it occupies a volume of 48cm3, what is its density?​
NNADVOKAT [17]

Answer:

The answer is

<h2>0.052 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 2.5 g

volume = 48 cm³

The density is

density =  \frac{2.5}{48}   \\  = 0.052083333...

We have the final answer as

<h3>0.052 g/cm³</h3>

Hope this helps you

3 0
3 years ago
Chemistry gcse
mart [117]
Yes, anything with carbonate, hydrogen carbonate (bicarbonate) at the end is a carbonate.

Examples:NaHCO3 (Sodium hydrogen carbonate or Sodium bicarbonate)Na2CO3 (Sodium carbonate)
8 0
3 years ago
A chemical reaction is the process by which a ___ takes place
Verizon [17]
A chemical reaction is the process by which a CHANGE takes place (?)
4 0
3 years ago
Read 2 more answers
Write a balanced half-reaction for the oxidation of aqueous hydrazine N2H4 to gaseous nitrogen N2 in basic aqueous solution
Zigmanuir [339]

Answer:

N2H2(aq) + 2OH^-(aq) ----------> N2(g) + 2H2O(l) + 2e

Explanation:

Hydrazine is mostly used in thermal engineering as an anticorrosive agent. Hydrazine can be oxidized in aqueous solution as shown in the equation above. Oxidation has to do with loss of electrons and increase in oxidation number.

The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.

7 0
3 years ago
Given that 7.25 moles of carbon monoxide gas are present in a container of volume 11.90 L, what is the pressure of the gas (in a
d1i1m1o1n [39]

Answer:17.955atm

Explanation:Pv=nrt

P= nrt/v

P= 7.25*0.08205*360/11.90

P= 214.1505/11.90

P=17.995atm

6 0
3 years ago
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