<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Answer:
da answerr is six
if DF is 6 and all sides are equal in length the EF side is going to be 6 as well
Answer:
length x width divided by 2
Step-by-step explanation:
Answer:
Charlie had 1340 more stamps than Ryan
Step-by-step explanation:
altogether, they have 1608 stamps.
Because if Charlie has 5 times more plus Ryan's portion equals 6 portion total.
Divide 1608 by 6 and that equals 268
Meaning that Ryan has 268 stamps.
To confirm, subtract 268 from 1608
this equals 1340.
268 * 5 = 1340
Area = length * width = 4x * x = 4x^2.
4x^2 = 80
x^2 = 80/4 = 20
x = sqrt 20
Answer is 4.47 to nearest hundredth.
