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Zarrin [17]
3 years ago
9

How do you do percent problems

Mathematics
1 answer:
kupik [55]3 years ago
6 0

Answer:

so say you have 76%+52% you would just type 76% in to you'r calculator and you would get .76 and if you do the same for 52% you would get .52 so it would be .76+.52. Hope this makes sense :)

Step-by-step explanation:

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HELPPP ASAP WILL MARK BRAINILEST
Alenkasestr [34]

Andy is correct! Andy has the function 4, his leading coefficient is negative, and his functions contains zeros. Hope this helps!

7 0
3 years ago
A triangle has side lengths of (7x-4)(7x−4) centimeters, (x+3)(x+3) centimeters, and (3y+2)(3y+2) centimeters. Which expression
Papessa [141]

Answer:

<u>This assumes that the question was meant to read:</u>

"A triangle has side lengths of (7x−4) centimeters, (x+3) centimeters, and (<u>3x+2</u>) centimeters."  <u>And not </u>"A triangle has side lengths of (7x-4)(7x−4) centimeters, (x+3)(x+3) centimeters, and (3y+2)(3y+2) centimeters."

If the revision is correct, the perimeter is 11x + 1 cm

=============================================

<u>If the question was correctly written, then answer is:</u>

50x^2 - 50x + 9y^2  + 12 y  + 29

===============

Step-by-step explanation:

  (7x-4) cm

+ (x+3)  cm

<u>+ (3x+2) cm</u>

11x + 1 cm

If the question was correctly written as is, then:

(7x-4)(7x−4) = 49x^2 - 56x + 16

+(x+3)(x+3)    =     + x^2   + 6x   + 9

+(3y+2)(3y+2) = <u> +9y^2  + 12 y  + 4</u>

                         50x^2 - 50x + 9y^2  + 12 y  + 29 cm

                       

8 0
2 years ago
3^(2x+3)=6^(x+2)<br><br> Please help
Nitella [24]
3^(2x+3)=6^(x+2)=STUDY
4 0
4 years ago
2x + 4y = 1<br> 3x - 5y = 7<br> solve the simultaneous equations x
Norma-Jean [14]

Answer:

(x,y)=(3/2, -1/2)

Step-by-step explanation:

2x+4y=1  /*3

3x-5y=7  /*(-2)

6x+12y=3

-6x+10y=-14

...........................

/      22y=-11

      y= -11/22

     y= -1/2

2x+4*(-1/2)=1

2x-2=1

+2     +2

2x=3

x=3/2

so the solutionis (x,y)=(3/2, -1/2)

7 0
3 years ago
The weight distribution of parcels sent in a certain manner is normal with mean value 15 lb and standard deviation 3.3 lb. The p
disa [49]

Answer: 23.7 lb

Step-by-step explanation:

Mean m = 15 lb

Standard deviation d = 3.3 lb

To determine the surcharge weight, we need to know the highest weight of 99% of the parcels.

P(z<x) = 0.99 = ¢(Z)

Z = 2.33

Since Z = (x - m)/d

x = dZ + m

x = 3.3*2.33 + 15

x = 22.689 lb approximately

x = 22.7 lb

Therefore, the highest weight for 99% if the parcels is 22.7 lb.

That is, the surcharge weight = 22.7 + 1 = 23.7 lb

3 0
3 years ago
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