You need to find the total distance and the total time. The total distance is two times the distance to school, 2d.s=d/t=>t=d/sWhere s is speed, d is distance and t is time. So the time taken to get to school is:d/s1and the time taken to get back is:d/s2so the total time is:d/s1+d/s2=d(1/s1+1/s2)So, as speed = distance/time, divide the total distance by the total time:2d/d(1/s1+1/s2)=2/(1/s1+1/s2)=2/(1/20+1/40)=80/3≈26.7km/hr
Answer:
the locus is the perpendicular bisector of the segment
Step-by-step explanation:
The points equidistant from A and B lie on the line that is the perpendicular bisector of segment AB.
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<em>Comment on this geometry</em>
You take advantage of this fact when you construct a circle through 3 points. You construct the perpendicular bisectors of segments between pairs of the points, and locate the center of your circle at their intersection.
Answer:
Step-by-step explanation:
x=135
y=45 b/c 180-135 = 45 & the angles are supplementary
: 1) If you were going to solve these, you would set them up like this.
s+p=19
7s+10p=121
among the choices, b is the only one that is equivalent to one of these equations
2) The problem looks a little confusing. If the price is per box then they easily make $275.
8b+9h=53
20*8b+30*9h=275
If it's per batch, the answer is B.
3. x^2+y^2=16
y=x+4
solve the first equation for y
y=√16-x^2
x+4=√16-x^2
(x+4)^2=16-x^2
x^2+8x+16=16-x^2
2x^2+8x=0
2x(x+4)=0
x=0 or x=-4
(be carefull i copyed and pasted the answer)
