The public library has an approximate length of 1 x 10^5 millimeters and width of 8 x 10^4 millimeters. what is the area, in squ
are milliters, of the public library?
a. 8 x 10^9 square millimeters
b. 9 x 10^9 square millimeters
c. 8 x 10^20 square millimeters
d. 9 x 10^20 square millimeters
1 answer:
Area = length*width
.. = (1*10^5 mm)*(8*10^4 mm)
.. = (1*8)*10^(5+4) mm^2
.. = 8*10^9 mm^2
Selection A is appropriate.
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