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bulgar [2K]
2 years ago
9

13x + 2y - 6x + 8 A little help

Mathematics
2 answers:
kirill [66]2 years ago
8 0

Answer:

7x+2y+8 if you just do this equation regularly but in point intercept from it would be

2y=7x+8

then divided the others by 2y and you get

y=3.5x+8

Step-by-step explanation:

storchak [24]2 years ago
5 0

Answer:

7x + 2y + 8

......................................................................................................................................................................................................................................................................................................

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Anyone know this Geometry problem?
Yuliya22 [10]

Answer:

ST = 20

Step-by-step explanation:

RT is the sum of RS and ST

Replacing with length you get:

17 + x + 6 = 3x - 56

17 + 6 + 5 = 3x - x

28 = 2x

14 = x

ST = x + 6 = 14 + 6 = 20

6 0
3 years ago
What is the value of the expression 3x-8y when x=10 and y=2?
Greeley [361]

Answer:

14

Step-by-step explanation:

3x-8y

(3*10)-(8*2)

30-16

14

7 0
3 years ago
Read 2 more answers
Joe tracked the height of his Dalmatian puppy from age 13 weeks to 25 weeks. He graphed the data and determined the line of best
nadya68 [22]

Answer:

22.5 weeks

Step-by-step explanation:

y = 1.12x + 28.78 represents the height of the puppy.  Here that height is 54 cm:

Then 54 = y = 1.12x + 28.78

Combining the constants, we get 1.12x = 25.22.  Dividing both sides by 1.12, x turns out to be 22.5 weeks.

3 0
2 years ago
Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0   is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

                 =  x² + x(-r - s) +  rs

or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

⇒  b +  s = - r

or, s  = -r - b

Now, given : r = Rational  and the negative of a rational is also rational.

⇒  -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0   is also rational number.

7 0
3 years ago
Will mark brainliest !!!
Wittaler [7]

Answer:

just mark points it is very easy

5 0
2 years ago
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