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Agata [3.3K]
3 years ago
10

A set of data whose histogram is extremely skewed yields a sample mean and standard deviation of 68.5 and 12.75, respectively. W

hat is the minimum percentage of observations that:
A. are between 43 and 94.

Percentage = At Least %

B. are between 30.25 and 106.75.

Percentage = At Least %
Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0


any other questions or comments about this.
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If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
In circle C, r = 32 units.
vlabodo [156]
Probably 2561 but since area equal r^2 I thought it would be 3217
5 0
3 years ago
The question is on the picture i need the full answer to both
Archy [21]

Answer:

Sorry don't know the answer

6 0
2 years ago
Read 2 more answers
PLEASE HELP!!! ILL GIVE BRAINLIEST<br><br><br> what is the function rule is slope
sergey [27]

Answer:

here!

Step-by-step explanation:

How to write a function rule using the concept of slope. Let us do this for example #3. The goal is use the equation y = mx + b. y = 4x + b. Use (1,6) to find b. 6 = 4 + b.

8 0
2 years ago
A rectangular garden is 8 feet long and 4 feet wide. A second rectangular garden has dimensions that are 54 the dimensions of th
Y_Kistochka [10]
We have the perimeter of first dimension 2(8 + 4) = 24;
The perimeter of the second dimension is 2( 8 + 54 + 4 + 54 ) = 240
We calculate p/100 = 24/240;
Then p/100 = 1/10;
p = 100/10;
p = 10;
Finally, 10% is the answer.
8 0
3 years ago
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