Sentences for chemical energy

What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on and overla

jok3333 [9.3K]

Answer:

Electron-pair geometry: tetrahedral

Molecular geometry: trigonal pyramidal

Hybridization: sp³

sp³ - 4 p

Explanation:

There is some info missing. I think this is the original question.

<em>For NBr₃, What are its electron-pair and molecular geometries? What is the hybridization of the nitrogen atom? What orbitals on N and Br overlap to form bonds between these elements?</em>

<em>The N-Br bonds are formed by the overlap of the ___ hybrid orbitals on nitrogen with ___ orbitals on Br.</em>

<em />

Nitrogen is a central atom surrounded by 4 electron domains. According to VESPR, the corresponding electron-pair geometry is tetrahedral.

Of these 4 electron domains, 3 represent covalent bonds with Br and 1 lone pair. According to VESPR, the corresponding molecular geometry is trigonal pyramidal.

In the nitrogen atom, 1 s orbital and 3 p orbitals hybridize to form 4 sp³ orbitals for each of the electron domains.

The N-Br bonds are formed by the overlap of the sp³ hybrid orbitals on nitrogen with 4p orbitals on Br.

7 0

3 years ago

How many mol of C7H16 would you have if you have 76.36 grams? Give your answer to 2 decimal spaces.

tensa zangetsu [6.8K]

0.761 mol of $C_7H_{16}$ would you have if you have 76.36 grams.

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass=76.36 grams

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{76.36 grams}{100.21 g/mol}$

Moles = 0.761

Hence, 0.761 mol of $C_7H_{16}$ would you have if you have 76.36 grams.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

7 0

2 years ago

How can you remember an individual element's ionic charge?

docker41 [41]

Answer:

write it down

Explanation:

6 0

3 years ago

Read 2 more answers

2. A block of material has a volume of 2 m3. It has a mass of 1 × 104 kg. Calculate the density of the material sample and expre

maks197457 [2]

Density = mass / volume

D = 1 x 10⁴ / 2

D = 5000 kg/m³ in g/cm³:

1 kg/m³ ---------------- 0.001 g/cm³
5000 kg/m³ ----------- ??

5000 x 0.001 / 1 => 5.0 g/cm³

hope this helps!

7 0

3 years ago

An experiment shows that a 250 ?ml gas sample has a mass of 0.430 g at a pressure of 736 mmhg and a temperature of 28 ?c.

dmitriy555 [2]

What we're looking for here is the gas sample's molar mass given its mass, pressure, volume, and temperature. Recalling the gas law, we have

$PV = nRT$ or
$n = \frac{PV}{RT}$

where R is <span>0.08206 L atm / mol K, P is the given pressure, T is the temperature, and V is the volume.

Before applying the values given, it is important to make sure that they are to be converted to have consistent units with that of R.
</span>
Thus, we have

P = 736/ 729 = 0.968 atm
T = 28 + 273.15 = 301.15 K
V = 250/1000 = 0.250 L

Now, applying these converted values into the gas law, we have

$n = \frac{(0.968 atm)(0.250 L)}{(0.08206 L.atm/mol.K)(301.15 K)}$
$n = 0.00979 moles$

Given that the mass of the sample is 0.430 g, we have

$molar mass = \frac{mass}{number of moles}$
$molar mass = \frac{0.430}{0.00979} = 43.9$

Thus, the gas sample has a molar mass of 43.9 g/mol.

4 0

3 years ago