Metals combine with nonmetals to give ionic compounds. When naming binary ionic compounds, name the cation first (specifying the charge, if necessary), then the nonmetal anion (element stem + -ide). Hope this helps!
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Answer:
The equilibrium constant in terms of concentration that is,
.
Explanation:

The relation of
is given by:

= Equilibrium constant in terms of partial pressure.=98.1
= Equilibrium constant in terms of concentration =?
T = temperature at which the equilibrium reaction is taking place.
R = universal gas constant
= Difference between gaseous moles on product side and reactant side=



The equilibrium constant in terms of concentration that is,
.
I put the answer <em>C: Keq will increase</em>, on PLATO. Hope this works for you!