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joja [24]
2 years ago
9

(12pts) Separation of Copper(II) and Bismuth(III) Ions Procedure Number and Ion Test Reagent or Technique Evidence of Chemical C

hange Chemical(s) Responsible for Observation [6] Cu2 NH4OH Deep blue solution [Cu(NH3)4]2 [7] Cu2 C-Test K4[Fe(CN)6] Red brown ppt K2[Fe(CN)6] [8] Bi3 NH4OH White ppt Bi(OH)3 [9] Bi3 C-Test Na2Sn(OH)4 Black ppt Bi (12pts) Enter the chemical equations for the test and the confirmation test.
Chemistry
1 answer:
anastassius [24]2 years ago
3 0

Answer:

attached below

Explanation:

write the chemical equations for the test  and confirmation test

i.e.

i)Chemical equation for main copper test

ii)Chemical equation for copper confirmation test

iii)Chemical equation for main bismuth test

iv) Chemical equation for bismuth confirmation test

attached below are the chemical equations for the test and confirmation test

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Question 10 (1 point)
levacccp [35]
The empirical formula gives the relative ratio of atoms in each element. Therefore, it simplifies the whole numbers. For example C2H6 can be reduced to CH3 because they share the greatest common factor (2). The answer to this question would be #1. C4H10 can be reduced to C2H5 because 4 and 10 are both divisible by 2. C2H5 can not be reduced any further. All of the other options do not have a greatest common factor making them a empirical formula.
4 0
2 years ago
The most unusual characteristic of Uranus is _____.
fiasKO [112]

Answer:

the axis is tilted at 98 degrees

Explanation:

Uranus is blue, not green; it has an atmosphere of hydrogen and helium, not methane.  While it does have an icy cold temperature, that's not a very unusual characteristic for an outer planet.  However, the tilt of the axis is unusual; no other planet is tilted almost completely on its side!

6 0
3 years ago
What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The
Effectus [21]

<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.

<u>Explanation:</u>

For the given nuclear reaction:

_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}

We are given:

Mass of _{19}^{40}\textrm{K} = 39.963998 u

Mass of _{20}^{40}\textrm{Ca} = 39.962591 u

To calculate the mass defect, we use the equation:

\Delta m=\text{Mass of reactants}-\text{Mass of products}

Putting values in above equation, we get:

\Delta m=(39.963998-39.962591)=0.001407u

To calculate the energy released, we use the equation:

E=\Delta mc^2\\E=(0.001407u)\times c^2

E=(0.001407u)\times (931.5MeV)    (Conversion factor:  1u=931.5MeV/c^2  )

E=1.3106MeV

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0
3 years ago
If you start with 0.30 m mn2 , at what ph will the free mn2 concentration be equal to 4.6 x 10-11 m?
aksik [14]

If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

Initial molarity of Mn₂ = 0.30 M

Final molarity of Mn₂ = 4.6 x 10⁻¹¹

pH = ?

Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

    Mn(OH)₂   →    Mn⁺² + 2OH⁻

    [Mn⁺²] = 4.6 x 10⁻¹¹

We will calculate the concentration of OH⁻ by using Ksp expression

    Ksp = [Mn⁺²][OH-]²

    [Mn⁺²][OH⁻]² = 4.6 x 10⁻¹⁴

    [OH⁻]² = 4.6 x 10⁻¹⁴ / 4.6 x 10⁻¹¹

    [OH⁻]² = 10⁻³

    [OH⁻] = (10⁻³)¹⁽²

    [OH⁻] = 0.0316 M

Calculate the pOH

    pOH = -log [OH⁻]

    pOH =  -log [0.0316]

    pOH = 1.5

Now calculate pH

   pH = 14 - pOH

   pH = 14 - 1.5

   pH = 12.5

You can also learn about molarity from the following question:

brainly.com/question/14782315

#SPJ4

7 0
1 year ago
I NEED HELP WITH #3 pleaseeee
Anit [1.1K]

Answer:

energy level

sub energy level

electrons in the orbital

Explanation:

3 0
3 years ago
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