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3 years ago

Is tea a pure substance?

2 answers:

7 0

Answer: Tea would be a solution that is made of different compounds of water that would be separated by tea leaves from it's homogeneous mixture it would be a chemical substance not a pure substance!

Explanation: Have a Great Day! =)

maks197457 [2]3 years ago

3 0

Answer: no tea is not a pure substances

Explanation:

A Tea is a solution of compounds in water, so it is not chemically pure. It is usually separated from tea leaves by filtration. B Because the composition of the solution is uniform throughout, it is a homogeneous mixture. ... A Aluminum oxide is a single, chemically pure compound.Sep 18, 2019

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You wish to make a compound of cerium and oxygen. The formula for the compound is Ce2O3. If 2.00 grams of cerium were available

almond37 [142]

Answer:

The volume of STP will be 0.03 plss mark me brainliest

7 0

3 years ago

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

Two or more atoms chemically bonded together are called

BARSIC [14]

Answer:

A compound is "a substance formed when two or more chemical elements are chemically bonded together." There are two main types of chemical bonds: covalent and ionic.

Explanation:

Hope this helps!

8 0

3 years ago

Garfield (weighing 24 lbs) took a flight to the moon on the space shuttle. As usual, he stuffed himself with lasagna during the

Nata [24]

Answer:

Yes, it is due to the gravitational pull from the moon

Explanation:

The mass of Garfield didn't change during the flight, which is to say, the amount of matter in his body is the same on Earth as on the Moon.

However, <em>weight is a measurement of how strongly mass is pulled towards the ground, due to the gravitational pull.</em>

So even though Garfield's mass is the same, the weight is less due to the lower gravitational pull from the Moon compared to Earth (the weight is one-sixth of the original weight as gravity on the moon is about one-sixth of Earth's). When Garfield returns to Earth, the scale will still read 24 lbs.

4 0

3 years ago

How many molecules of n2 are in a 200.0 ml container at 780 mmhg and 135∘c?

Neporo4naja [7]

By use of ideal gas equation PV= nRT where n is the number of moles,P = pressure, V = volume, R= gas constant (0.08206 L. atm/ mol.k) ant T is the temperature,

to calculate the number of moles(n) =PV/RT

convert ml to L, that is 200/1000= 0.2 L

convert mmHg to atm, that is 780mm hg x 1atm/ 760 mm hg= 1.026 atm

convert temperature to kelvin, that is 135 +273= 408 k
n is therefore= (0.2 x 1.026)/ ( 0.08206 x 408)= 6.129 x10^-3 moles

from avogadro constant 1moles = 6.02 x10^23 molecules what about 6 .129 x10^-3 moles

= ( 6.02 x10^23) x (6.129 x10^-3)/ 1mole = 3.69 x10^21 molecules

8 0

3 years ago