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grigory [225]
3 years ago
7

What is the hybridization of carbon in nco-?

Chemistry
2 answers:
never [62]3 years ago
5 0

Answer : The hybridization of carbon in NCO^- is, sp hybridized.

Explanation :

As we know that when a carbon attached to the four single sigma bonds then the hybridization will be, sp^3.

When a carbon attached to the three single sigma bonds and one-\pi bond that means a carbon bonded to another atom by the double bond then the hybridization will be, sp^2.

When a carbon attached to the two single sigma bonds and two-\pi bonds that means a carbon bonded to another atom by the triple bond then the hybridization will be, sp.

As per question, the given molecule is, NCO^-. In this molecule, a triple bond is present between the nitrogen and carbon atom and a single bond is present between the carbon and oxygen atom. That means, a carbon bonded to another atom by the triple bond then the hybridization will be, sp.

Hence, the hybridization of carbon in NCO^- is, sp hybridized.

Svet_ta [14]3 years ago
4 0

First let us see what kind of bonds are formed in the compound. By drawing the structure, we see that the kind of bonds are:

N =- triple bond -= C – O

<span>So there is only single bond between C and O therefore the hybridization of C is sp.</span>

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krek1111 [17]
First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
Co=58.933
Cl=35.45
H=1.008
O=15.999

Now, let's find the mass of each compound.

CoCl_2=58.933+2(35.45)=129.833
H_2O=2(1.008)+15.999=18.015

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

6(18.015)=108.09
129.833+108.09=237.923

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

\dfrac{108.09}{237.923}

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Turn that into a percentage and you get 45.431%.
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6 0
3 years ago
A sample of SO2 gas occupies 45.6 L at 373 K and 3.45 atm. This sample contains how many moles of oxygen atoms?
lisov135 [29]

Answer:

10.28 mol

Explanation:

S + 2O = SO2

(atm x L) ÷ (0.0821 x K)

(3.45 x 45.6) ÷ (0.0821 x 373)

=5.13726

Then round it to significant figures

=5.14

5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)

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5 0
4 years ago
What is the total volume of solution that was dispensed from this burette? before <br><br> after
monitta
Yeah answer should be .6 ml
6 0
3 years ago
Read 2 more answers
PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

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3 years ago
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