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lapo4ka [179]
3 years ago
15

The sum of three times a number b and 33 is at least 35

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
I love these problems, because it's just about reading the question. All you need to do is break it down. What do we know the "sum of" something is? We know that it means addition. What are we adding? "three times a number b and 33". Well, how can we express "three times b"? 3b! Right! Well, we know we're adding that to 33, so you're almost done. Right now you should have 3b+33. And what <em>is</em> 3b+33? at least 33. How can we express "at least"? >=, greater than or equal to, right! Finally, we have our answer. 3b+33>=35.
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Step-by-step explanation:

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Step-by-step explanation:

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liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

10x + 4y < 12

8x - 3y > 20

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

10x + 4y < 12

10 * 3 + 4 * -8 < 12

30 - 32 < 12

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8x - 3y > 20

8 * 3 - 3 * -8> 20

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(2, 5)

x = 2 and y = 5

10x + 4y < 12

10 * 2 + 4 * 5 < 12

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(-5, 1)

x = -5 and y = 1

10x + 4y < 12

10 * -5 + 4 * 1 < 12

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8x - 3y > 20

8 * -5 - 3 * 1 > 20

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(10, 3)

x = 10 and y = 3

10x + 4y < 12

10 * 10 + 4 * 3 < 12

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(2, -10)

x = 2 and y = -10

10x + 4y < 12

10 * 2 + 4 * -10 < 12

-20 < 12 --- True

8x - 3y > 20

8 * 2 - 3 * -10 > 20

46 > 20 --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

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