I believe it’s c good luck!
In order to find the vector that points from A to B we need to subtract each component of A from the corresponding component of B, according to the formula:
v(a→b)=(b1−a1,b2−a2)
In this case we have :
v(a→b)=(−5−(−8),3−(−1))
<span>v(a→b)=(3,4)
</span>To find the magnitude we use the formula:
||v|= √(v1^2)+(v1^2)
So:
||v|= √(32)+(42)
||v|= √9+16
||v|= <span>√</span>25
||v|= 5
They are exactly the same thing
Answer:
<em>y=-5</em>
Step-by-step explanation:
<u>Equation of the line</u>
Lines can be expressed in several forms. The slope-intercept form of the line is:
y = mx + b
Where m is the slope of the line and m is the y-intercept.
If the line is perpendicular to the y-axis, then it's a horizontal line. Horizontal lines have slope m=0, thus, the equation is:
y = b
To find the value of b, just substitute the given point:
-5=b
The equation of the line is:
y=-5
Answer:
2a² + a ( or a(2a+1) )
Step-by-step explanation:
(6a²+3a) - (4a² + 2a) (expand parentheses)
= 6a²+3a - 4a² - 2a (group like terms)
= 6a²- 4a²+3a- 2a
= 2a² + a
= a(2a+1)
