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mixas84 [53]
3 years ago
8

How does real fingerprint analysis differ from the fingerprint analysis shown on television programs such as CSI?

Business
2 answers:
Zolol [24]3 years ago
8 0
Nowadays the FBI and all that take ink and put your finger prints in your file, but in CSI they just have your finger prints on the data base over the computer saved... Hope this helped!!
qaws [65]3 years ago
3 0

Answer:

In the television show they run the fingerprint through a machine in which they run it through a data base to see if it matches any previous criminals' prints, but in reality they actually have to find the person and then compare the fingerprints.  

Explanation:

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A doctor wants to estimate the hdl cholesterol of all? 20- to? 29-year-old females. how many subjects are needed to estimate the
Ira Lisetskai [31]

 

Given the following:

Sigma                                 = 17.8

E                                         = 44 points

Confidence interval        = 99% - 2.58

Confidence interval        = 95% - 1.96

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For 95% confidence level

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As we decrease the confidence level, from 99% to 95%, our confidence interval gets smaller. In additional, to be more confident that our interval actually comprises the population mean we have to increase the size of the interval. To ease that trade off between level of confidence and the precision of our interval is to primarily increase the sample size. 

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3 years ago
One of the questions in the Pew Internet &amp; American Life Project asked adults if they used the Internet at least occasionall
g100num [7]

Answer:

Explanation:

S/N   Age range       Adult Population       Population Internet Users

A       18   -    29                 478                                 454

B       30   -    49                833                                 741

C       50 and above         1644                                1058

             Total                     2955                               2253

a) Let E = Estimate proportion and A = Internet users

Hence, n(E) = 478 and n(A) = 454

∴ Probability of Internet users (18 - 29), P(A) = n(A)/n(E) = 454/478 = 0.9498 (94.98%)

b) n(E) = 833 and n(B) = 741

∴ Probability of Internet users (30 - 49), P(B) = n(A)/n(E) = 741/833 = 0.8896 (88.96%)

c) n(E) = 1644 and n(C) = 1058

∴ Probability of Internet users (50 and above), P(C) = n(C)/n(E) = 1058/1644 = 0.6436 (64.36%)

d) Let Et = Total estimate proportion

Hence, n(Et) = 2955 and n(A) = 454

∴ Probability of 18 - 29 age range using Internet overall Pt(A) = n(A)/n(Et) = 454/2955 = 0.1536 (15.36%)

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3 years ago
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Hence we can conclude that Nancy has to perform exploratory research.

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