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3 years ago

Which statements are true regarding the data displayed in the box plots? Check all that apply

Mathematics

2 answers:

sleet_krkn [62]3 years ago

3 0

Answer:

b , c , d , e

Step-by-step explanation:

the last 4 just did it

liq [111]3 years ago

3 0

Answer:

B, C, D, E

Step-by-step explanation:

The range in data for the oyster volume is greater than for the mussel volume.

Oysters tend to have more volume than mussels.

The IQR is less for the mussel volume than for the oyster volume.

There is greater variation of oyster volumes than mussel volumes.

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Courtney works for the Red Cross and has been tasked with buying non-perishable items for families recently displaced by a hurri

beks73 [17]

9514 1404 393

Answer:

x + y = 20
20x +30y = 450

Step-by-step explanation:

The equation for the total number of cases is ...

x + y = 20

The equation for the total cost of the cases is ...

20x +30y = 450

_____

<em>Additional comment</em>

The solution to these equations is (x, y) = (15, 5).

5 0

2 years ago

Match each vector operation with its resultant vector expressed as a linear combination of the unit vectors i and j.

Cloud [144]

Answer:

3u - 2v + w = 69i + 19j.

8u - 6v = 184i + 60j.

7v - 4w = -128i + 62j.

u - 5w = -9i + 37j.

Step-by-step explanation:

Note that there are multiple ways to denote a vector. For example, vector u can be written either in bold typeface "u" or with an arrow above it $\vec{u}$ . This explanation uses both representations.

$\displaystyle \vec{u} = \langle 11, 12\rangle =\left(\begin{array}{c}11 \\12\end{array}\right)$ .

$\displaystyle \vec{v} = \langle -16, 6\rangle= \left(\begin{array}{c}-16 \\6\end{array}\right)$ .

$\displaystyle \vec{w} = \langle 4, -5\rangle=\left(\begin{array}{c}4 \\-5\end{array}\right)$ .

There are two components in each of the three vectors. For example, in vector u, the first component is 11 and the second is 12. When multiplying a vector with a constant, multiply each component by the constant. For example,

$3\;\vec{v} = 3\;\left(\begin{array}{c}11 \\12\end{array}\right) = \left(\begin{array}{c}3\times 11 \\3 \times 12\end{array}\right) = \left(\begin{array}{c}33 \\36\end{array}\right)$ .

So is the case when the constant is negative:

$-2\;\vec{v} = (-2)\; \left(\begin{array}{c}-16 \\6\end{array}\right) =\left(\begin{array}{c}(-2) \times (-16) \\(-2)\times(-6)\end{array}\right) = \left(\begin{array}{c}32 \\12\end{array}\right)$ .

When adding two vectors, add the corresponding components (this phrase comes from Wolfram Mathworld) of each vector. In other words, add the number on the same row to each other. For example, when adding 3u to (-2)v,

$3\;\vec{u} + (-2)\;\vec{v} = \left(\begin{array}{c}33 \\36\end{array}\right) + \left(\begin{array}{c}32 \\12\end{array}\right) = \left(\begin{array}{c}33 + 32 \\36+12\end{array}\right) = \left(\begin{array}{c}65\\48\end{array}\right)$ .

Apply the two rules for the four vector operations.

$\displaystyle \begin{aligned}3\;\vec{u} - 2\;\vec{v} + \vec{w} &= 3\;\left(\begin{array}{c}11 \\12\end{array}\right) + (-2)\;\left(\begin{array}{c}-16 \\6\end{array}\right) + \left(\begin{array}{c}4 \\-5\end{array}\right)\\&= \left(\begin{array}{c}3\times 11 + (-2)\times (-16) + 4\\ 3\times 12 + (-2)\times 6 + (-5) \end{array}\right)\\&=\left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle\end{aligned}$

Rewrite this vector as a linear combination of two unit vectors. The first component 69 will be the coefficient in front of the first unit vector, i. The second component 19 will be the coefficient in front of the second unit vector, j.

$\displaystyle \left(\begin{array}{c}69\\19\end{array}\right) = \langle 69, 19\rangle = 69\;\vec{i} + 19\;\vec{j}$ .

$\displaystyle \begin{aligned}8\;\vec{u} - 6\;\vec{v} &= 8\;\left(\begin{array}{c}11\\12\end{array}\right) + (-6) \;\left(\begin{array}{c}-16\\6\end{array}\right)\\&=\left(\begin{array}{c}88+96\\96 - 36\end{array}\right)\\&= \left(\begin{array}{c}184\\60\end{array}\right)= \langle 184, 60\rangle\\&=184\;\vec{i} + 60\;\vec{j} \end{aligned}$ .

$\displaystyle \begin{aligned}7\;\vec{v} - 4\;\vec{w} &= 7\;\left(\begin{array}{c}-16\\6\end{array}\right) + (-4) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}-112 - 16\\42+20\end{array}\right)\\&= \left(\begin{array}{c}-128\\62\end{array}\right)= \langle -128, 62\rangle\\&=-128\;\vec{i} + 62\;\vec{j} \end{aligned}$ .

$\displaystyle \begin{aligned}\;\vec{u} - 5\;\vec{w} &= \left(\begin{array}{c}11\\12\end{array}\right) + (-5) \;\left(\begin{array}{c}4\\-5\end{array}\right)\\&=\left(\begin{array}{c}11-20\\12+25\end{array}\right)\\&= \left(\begin{array}{c}-9\\37\end{array}\right)= \langle -9, 37\rangle\\&=-9\;\vec{i} + 37\;\vec{j} \end{aligned}$ .

7 0

3 years ago

Many manufacturers have quality control programs that include inspection of incoming materials for defects. Suppose a computer m

Readme [11.4K]

Answer:

a) (1,2), (1,3), (1,4), (1,5), (2,3), (2,4),(2,5),(3,4), (3,5) and (4,5)

PX(0) = 0.3

PX(1) = 0.6

PX(2) = 0.1

F(x) = 0 if x<0
F(x) = 0.3 if 0 ≤ x < 1
F(x) = 0.9 if 1 ≤ x < 2
F(x) = 1 if x ≥2

Step-by-step explanation:

Lets call the boards 1,2,3,4 and 5

a) There are ${5 \choose 2} = 10$ possible outcomes: (1,2), (1,3), (1,4), (1,5), (2,3), (2,4),(2,5),(3,4), (3,5) and (4,5).

b) X is 0 if the selected boards doesnt contain 1 or 2. There are ${3 \choose 2} = 3$ possibilities for this, in concrete, (3,4), (3,5) and (4,5).

PX(0) = 3/10 = 0.3

There is only 1 possibility so that X = 2, which is (1,2), therefore

PX(2) = 1/10 = 0.1

In any other case (there are 6 remaining), X will be equal to 1, so

PX(1) = 6/10 = 0.6

Therefore, X has the following distribution

PX(0) = 0.3

PX(1) = 0.6

PX(2) = 0.1

c) F(0) = 0.3

F(1) = 0.3+0.6 = 0.9

F(2) = 1

We have, as a consequence

F(x) = 0 if x<0
F(x) = 0.3 if 0 ≤ x < 1
F(x) = 0.9 if 1 ≤ x < 2
F(x) = 1 if x ≥2

3 0

3 years ago

It takes 11 ounces of oatmeal to make 1 serving. How many servings are

Rzqust [24]

Answer:

I think its 1.56

Step-by-step explanation:

if its right can I please get the brainlest

5 0

3 years ago

NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.

Len [333]

Answer:

A:(-2,-3)

B:(-4.009,1.018) And (-2,-3)

C:x≈0,1.61878812

Step-by-step explanation:

I found the equations

g(x)=e^x+1

p(x)=5/2x+2

f(x)=-2x-7

plugged it in on a graph found the answer to find g(x) all you need to do is know the parent function y=e^2(exponential) and I found where the lines intersect for part A and B and or p(x)=g(x) I did e^x+1=(5/2)x+2

7 0

3 years ago