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Assoli18 [71]
3 years ago
5

Evaluate 5-4÷(6-(3-1))

Mathematics
1 answer:
FromTheMoon [43]3 years ago
8 0
You want to use PEMDAS (parentheses exponents multiplication division adding subtracting) for this

5-4\(6-2)
(Did 3-1)

5-4\4
(Did 6-2)

5-1
(Divide 4 by 4 )

=4
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Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form. (2 points)
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Answer:

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The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

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