Answer:
hjv j
Step-by-step explanation:
kkj
Hi there!

To find the indefinite integral, we must integrate by parts.
Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":
u = 4x
du = 4
dv = cos(2 - 3x)
v = 1/3sin(2 - 3x)
Write into the format:
∫udv = uv - ∫vdu
Thus, utilize the solved for expressions above:
4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx
Simplify:
-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx
Integrate the integral:
∫4/3(sin(2 - 3x)dx
u = 2 - 3x
du = -3dx ⇒ -1/3du = dx
-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C
Combine:

What would you like help with?
Answer:
1/16 or 0.0625
Step-by-step explanation:
we can take 4 outside the parentheses and we would get 4^(4-7+1)=4^(-2)= 1/(4^2)=1/16=0.0625.
Diagonals of a parallelogram bisect each other. It is not relevant that PN=9. since AO=4 then AM=4