The answer is the first option
Answer:
12x^5
Step-by-step explanation:
(-2x)(-6x^4)
Multiply the numbers
-2 * -6 = 12
Multiply the variables
x* x^4 = x^5
12x^5
Answer:
GCF=4
Step-by-step explanation:
16/4=4
24/4=6
36/4=9
Answer:
a. 
b. 
Step-by-step explanation:
First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

The rate is negative as it represents the amount of caffeine leaving the body at certain time.
Y-intercept = -5
slope = 5/2
Answer:
G