1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Temka [501]
3 years ago
7

The is a factor that's affected by changes in the independent variable

Physics
2 answers:
Aleks [24]3 years ago
8 0
<span>So we want to know what factor is affected by the changes of the independant variable. So if we have the form f(x)=x, x would be the independant variable and when we change the value of that variable we directly change the dependant variable, because the value of the dependant variable is dependant of the independant variable. </span>
inna [77]3 years ago
8 0

Dependent  variable.......

You might be interested in
When energy is produced in a reaction it
goblinko [34]
The correct answer is b i believe
4 0
3 years ago
Free 25 points cause why the hell not
hodyreva [135]

Answer:

I love nice people. Doing anything interesting for Thanksgiving?

4 0
4 years ago
Read 2 more answers
An experimenter adds 970 J of heat to 1.75 mol of an ideal gas to heat it from 10.0∘C to 25.0∘C at constant pressure. The gas do
ipn [44]

Answer:

(a) ΔU=747J

(b) γ=1.3

Explanation:

For (a) change in internal energy

According to first law of thermodynamics the change in internal energy is given as

ΔU=Q-W

Substitute the given values

ΔU=970J-223J

ΔU=747J

For(b) γ for the gas.

We can calculate γ by ratio of heat capacities of the gas

γ=Cp/Cv

Where Cp is the molar heat capacity at constant pressure

Cv is the molar heat capacity at constant volume

To calculate γ we first need to find Cp and Cv

So

For Cp

As we know

Q=nCpΔT

Cp=(Q/nΔT)

C_{p}=\frac{970J}{1.75mol*(25^{o}C-10^{o}C )}\\C_{p}=37J/mol.K

From relation of Cv and Cp we know that

Cp=Cv+R

Where R is gas constant equals to 8.314J/mol.K

So

C_{v}=C_{p}-R\\C_{v}=37-8.314\\C_{v}=28.687J/mol.K\\

So

γ=Cp/Cv

γ=[(37J/mol.K) / (28.687J/mol.K)]

γ=1.3

4 0
3 years ago
Find the velocity. 10 points. Will give brainliest!
BARSIC [14]

Answer:

6.060606...

Explanation:

To figure out velocity, you divide the distance by the time it takes to travel that same distance, then you add your direction to it. So the distance would be 1000m and the time would be 2 minutes and 45 seconds and if you convert the minutes into fractions you would get 165 seconds than you would divide 1000m by 165 seconds and you would get 6.060606... seconds as her average velocity

4 0
4 years ago
Jonathan has six strings that are the same thickness and are all the same material. He cuts the strings to different lengths and
harkovskaia [24]
The shortest string will have the highest pitch.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Please help on this one?
    8·1 answer
  • What does it mean when white light is diffracted and at a particular location the color seen is blue? Please use 2 content relat
    13·1 answer
  • How many feet are there in a meter?
    5·2 answers
  • When we talk about how a Ferrari obtains a top speed of 349 km/h, are we referring to average speed or instantaneous? How do you
    13·1 answer
  • Sierra did 500 J of work to move her couch. If she exerts 250 N of force on the couch, how far did she move it?
    9·1 answer
  • What is the number at the end of an isotope’s name?
    6·1 answer
  • A 55 year old woman is awakened by an excruciating pain that radiates from her right abdomen to her flank on the same side
    9·1 answer
  • Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitu
    8·1 answer
  • You want to average 90 km/h on a car trip. You cover the first half of the distance at an
    11·1 answer
  • When you’re driving on the freeway it’s necessary to keep your foot on the accelerator to keep the car moving at a constant spee
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!