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Salsk061 [2.6K]
3 years ago
6

You shove a chair with wheels(and let it go)and it starts moving across the floor. However,the chair soon shows down and comes t

o a complete stop. To keep the chair moving,you need to keep pushing on it.
This simple experiment implies that ;

A) Newton's first law,or the law of inertia,does not apply to a chair moving horizontally
B) The action-reaction forces act on the chair and cancel each other
C) A net force in the direction opposite to the motion of the chair acts to slow it down
D) The weight of the chair slows it down ​
Physics
2 answers:
raketka [301]3 years ago
5 0
I would say *B* because *D*dose not matter if it was heavier or lighter. And I’m pretty sure in reality the thing that’s stopping it is friction ‘laughing emoji’
GarryVolchara [31]3 years ago
4 0

Answer:

Personally I think, that the answer is B.

Explanation:

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How are heat and light waves produced on and in the sun?
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All of the electromagnetic energy radiated from the sun (and from
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8 0
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Read 2 more answers
Please help me with this
mezya [45]

Answer:

.067 so C

Explanation:

I asked my sister who is in 2nd grade and she said it was right so you are good! =). have a great day!

5 0
3 years ago
A 52 N sled is pulled across a cement sidewalk at constant speed. A horizontal force of 36 N is exerted. What is the coefficient
Andre45 [30]

Answer:

μ = 0.692

Explanation:

In order to solve this problem, we must make a free body diagram and include the respective forces acting on the body. Similarly, deduce the respective equations according to the conditions of the problem and the directions of the forces.

Attached is an image with the respective forces:

A summation of forces on the Y-axis is performed equal to zero, in order to determine the normal force N. this summation is equal to zero since there is no movement on the Y-axis.

Since the body moves at a constant speed, there is no acceleration so the sum of forces on the X-axis must be equal to zero.

The frictional force is defined as the product of the coefficient of friction by the normal force. In this way, we can calculate the coefficient of friction.

The process of solving this problem can be seen in the attached image.

5 0
3 years ago
A hose directs a horizontal jet of water, moving with a velocity of 20m/s, on to a vertical wall. The
just olya [345]
Force is defined as the rate of change of momentum.
The initial amount of momentum is mv because water stops when it hit the wall total change of momentum must be \Delta p=mv.
Now let's calculate the force.
F= \frac{dp}{dt}=\frac{d(mv)}{dt}=\frac{dm}{dt}v
We need to find \frac{dm}{dt}. This is the amount of water hiting the wall per second.
\frac{dm}{dt}=\rho Av
Our final formula would be:
F=\rho Avv=\rho Av^2
And now we can calculate the answer:
F=1000\cdot5\cdot 10^{-4}\cdot(20)^2=200 N


6 0
3 years ago
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