Which country sent the first artificial satellite into orbit?

A car traveling with 500,000 J of kinetic energy is brought to a kinetic energy of

allsm [11]

Answer:

33,333.33 N

Explanation:

Given that :

Initial kinetic energy = 500,000 J

Final kinetic energy = 100,000 J

Using the relation :

Force * time = change in momentum (Newton's law)

Force (F) * 0.12 = (500,000 - 100,000)

0.12F = 400,000 J

Force = (400,000 J) / 0.12s

Force = 33333.333

Force = 33,333.33 N

3 0

3 years ago

True or false

lions [1.4K]

As the car is moving it indicates that the kinetic energy is being represented. That's why I am pretty sure that this statement is correct! That's all you need to know to solve this. Regards!

6 0

4 years ago

The question ask:

abruzzese [7]

Answer:

$\theta=28.07^{\circ}$

Explanation:

Speed of van, v = 28 m/s

Radius of unbanked curve, r = 150 m

Let $\theta$ is the angle with the vertical. In case of banking of road,

$T\ cos\theta=mg$ .............(1)

And

$T\ sin\theta=\dfrac{mv^2}{r}$ ..........(2)

From equation (1) and (2) :

$tan\theta=\dfrac{v^2}{rg}$

$tan\theta=\dfrac{(28)^2}{150\times 9.8}$

$\theta=28.07^{\circ}$

So, the string makes an angle of 28.07 degrees with the vertical. Hence, this is the required solution.

4 0

3 years ago

A student put her ear on one end of a long piece of lead. She asked her friend to

Ludmilka [50]

1) The length of the lead is 1700 m

2) The frequency of the wave is 400 Hz

Explanation:

1)

The wave in this problem is a sound wave, which is produced by the vibrations of the particles of air. It is a type of longitudinal wave (which means that the vibrations occur back-and-forth along the direction of propagation of the wave).

The speed of a sound wave in air is approximately

v = 340 m/s

In this problem, the sound wave is heard after a time of

t = 5 s

after the shot. Therefore, the distance travelled by the wave in this time (and therefore, the length of the lead) is

$d=vt=(340)(5)=1700 m$

2)

The frequency of a wave is the number of complete cycles made by the wave in one second.

For the wave in this problem, we are told that the wave has 2000 whole wavelengths in 5 seconds: this means that the wave completes 2000 cycles in 5 seconds. Therefore, we can find the frequency by setting up the following proportion:

$\frac{2000}{5}=\frac{x}{1}$