1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s344n2d4d5 [400]
4 years ago
12

A flat polished area is turned through 15 degrees. If the angle of incidence is 20 degrees, what is the angle between the incide

nt ray and the reflected ray of the turned surface?
Physics
1 answer:
Ilya [14]4 years ago
7 0

Answer:

<h2>50°</h2>

Explanation:

Angle of rotation of the flat polished surface \theta = 15°

angle of incidence i = 20°

Since the polished surface is turned at an angle of 15°, the angle of reflection

r = 2\theta (Note that the angle of rotation only have effect of the angle of reflection)

r = 2*15 = 30°

The angle between the reflected ray and the incident ray will be equal to the sum of the angle of incidence and the angle of reflection i.e i+r

The angle between the reflected ray and the incident ray = 20°+ 30° = 50°

You might be interested in
Two long, straight wires are parallel and 10 cm apart.One carries a current of 2.0 A, the other a current of 5.0A. (a) If the tw
lubasha [3.4K]

Answer:

Explanation:

Given

Distance between two wires d=10 cm

Current value i_1=2 A

i_2=5 A

(a)If current flows in opposite direction

When current Flows in opposite direction the two wires will repel each other

Force due to current carrying wire F=\frac{\mu _0i_1i_2}{2\pi r}

F_{12}=F_{21}=\frac{\mu _0\times 2\times 5}{2\times \pi \times 0.1}

F_{12}=\frac{4\pi \times 10^{-7}\times 2\times 5}{2\pi \times 0.1}

F_{12}=2\times 10^{-5} N (Repulsive Force)

(b)If current is flowing in the same direction

When direction of current is same then force will be attractive in nature

F_{12}=F_{21}=\frac{\mu _0i_1i_2}{2\pi r}

F_{12}=\frac{4\pi \times 10^{-7}\times 2\times 5}{2\pi \times 0.1}

F_{12}=2\times 10^{-5} N (attractive Force)

5 0
4 years ago
An astronaut, whose mission is to go where no one has gone before, lands on a spherical planet in a distant galaxy.
NeTakaya

Answer:

M = 1.77 \times 10^{27} kg

Explanation:

As we know that the that the Astronaut dropped a stone on the surface of the planet takes 0.420 s to fall a distance of d = 1.90 m

so we will have

y = \frac{1}{2}g t^2

1.90 = \frac{1}{2}g(0.420^2)

g = 21.5 m/s^2

now we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

so we will have

21.5 = \frac{(6.67 \times 10^{-11})M}{(7.40\times 10^7)^2}

M = 1.77 \times 10^{27} kg

7 0
3 years ago
A 0.22kg mousetrap car has 3.1 J of potential energy due to the spring in the mouse
Stella [2.4K]

Answer:

r56

Explanation:

7 0
3 years ago
A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even thoug
vlada-n [284]

Answer:

The Minimum wavelength is  \lambda_{min}= 382.2nm

The Maximum wavelength is \lambda_{max}= 624.2nm

Explanation:

From the question we are told that  

              The energy range is  E_r = 3.25eV \ and  \ 19.9eV

   Considering E = 19.9eV

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

              E = 19.9eV = 19.9 *1.6 *10^{-19}J

This energy is mathematically represented as

                    E = \frac{hc}{\lambda_{max}}

Here h is the Planck's constant with value of  h= 6.625*10^{-34}J\cdot s

        c is the speed of light with value of  c = 3*10^8 m/s

Substituting values and making \lambda the subject of the formula

                       \lambda_{max} = \frac{hc}{E}

                         = \frac{6.625*10^{-34} * 3.0*10^{8}}{19.9*1.6*10^{-19}}

                         \lambda_{max}= 624.2nm

  Considering E = 3.25eV

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

              E = 19.9eV = 3.25 *1.6 *10^{-19}J

This energy is mathematically represented as

                    E = \frac{hc}{\lambda_{min}}

Substituting values and making \lambda the subject of the formula

                       \lambda_{min} = \frac{hc}{E}

                           = \frac{6.625*10^{-34} * 3.0*10^{8}}{3.25*1.6*10^{-19}}

                           \lambda_{min}= 382.2nm

3 0
3 years ago
A car slows down from 27.7 m/s to 10.9 m/s in 2.37 s, what is the acceleration?
larisa [96]

Answer:

Answer. to final velocity 'v' =10.9 m/s in time 't' = 2.37 secs. So acceleration = -7.09 m/sec^2 or, decceleration is 7.09 m/sec^2

Explanation:

4 0
3 years ago
Other questions:
  • In a chemical equation, the chemicals that react are considered . In a chemical equation, the chemicals that are produced are co
    15·2 answers
  • The two common forms of friction between two sliding surfaces presented in this course are _________ and kinetic friction.
    5·2 answers
  • How Antman can breathe when his size is smaller then oxygen molecules?​
    10·1 answer
  • How many valence electrons does pocl3 have? ...?
    10·1 answer
  • Use the drop-down menu to complete the statement. Based on the data in the line graph, you can predict there will likely be visi
    10·2 answers
  • We know velocity of sound v=a₩(omega), but speed does not depend on amplitude, why?
    12·1 answer
  • All of the following are bases except
    12·2 answers
  • If a substance containing charged ions and electrons can be compressed so that the particles have less space between them, the s
    14·2 answers
  • Which change occurs only in males during puberty
    8·1 answer
  • Which statement belongs to daltons atomic theory
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!