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SVETLANKA909090 [29]

3 years ago

6

A gas has an initial volume of 2.5 L at a temperature of 275 K and a pressure of 2.1 atm. The pressure of the gas increases to 2

.7 atm, and the temperature of the gas increases to 298 K. What is the final volume of the gas, rounded to the nearest tenth? 2.1 L 2.5 L 2.7 L 3.0 L

1 answer:

olchik [2.2K]3 years ago

7 0

Answer:

2.10L

Explanation:

Given data

V1= 2.5L

T1= 275K

P1= 2.1atm

P2= 2.7 atm

T2= 298K

V2= ???

Let us apply the gas equation

P1V1/T1= P2V2/T2

substitute into the expression we have

2.1*2.5/275= 2.7*V2/298

5.25/275= 2.7*V2/298

Cross multiply

275*2.7V2= 298*5.25

742.5V2= 1564.5

V2= 1564.5/742.5

V2= 2.10L

Hence the final volume is 2.10L

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