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SVETLANKA909090 [29]
3 years ago
6

A gas has an initial volume of 2.5 L at a temperature of 275 K and a pressure of 2.1 atm. The pressure of the gas increases to 2

.7 atm, and the temperature of the gas increases to 298 K. What is the final volume of the gas, rounded to the nearest tenth? 2.1 L 2.5 L 2.7 L 3.0 L
Physics
1 answer:
olchik [2.2K]3 years ago
7 0

Answer:

2.10L

Explanation:

Given data

V1= 2.5L

T1= 275K

P1= 2.1atm

P2= 2.7 atm

T2= 298K

V2= ???

Let us apply the gas equation

P1V1/T1= P2V2/T2

substitute into the expression we have

2.1*2.5/275= 2.7*V2/298

5.25/275= 2.7*V2/298

Cross multiply

275*2.7V2= 298*5.25

742.5V2= 1564.5

V2= 1564.5/742.5

V2= 2.10L

Hence the final volume is 2.10L

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Answer:

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Explanation:

From the question given above, the following data were obtained:

Mass (m) = 200 Kg

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Next, we shall determine the force exerted on the spring. This can be obtained as follow:

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Spring constant (K) = 10⁶ N/m

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1960 = 10⁶ × e

Divide both side by 10⁶

e = 1960 / 10⁶

e = 0.00196 m

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Spring constant (K) = 10⁶ N/m

Extention (e) = 0.00196 m

Energy (E) =?

E = ½Ke²

E = ½ × 10⁶ × (0.00196)²

E = 1.92 J

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g In a certain binary-star system, each star has the same mass which is 8.2 times of that of the Sun, and they revolve about the
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To solve this problem it is necessary to apply the concepts related to the Third Law of Kepler.

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From the mentioned star it is known that this is 8.2 time mass of sun and it is 6.2 times the distance between earth and the sun

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Substituting in Kepler's third law:

T^2 = \frac{4\pi^2 d^3}{2}

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T=\sqrt{\frac{4\pi^2(6.2*149.6*10^9)^3}{2(6.674*10^{-11} )(8.2*1.989*10^30)}}

T = 120290789.7s

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This is an object's change in motion per unit time in a specified direction.
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An object of mass kg is released from rest m above the ground and allowed to fall under the influence of gravity. Assuming the f
IgorLugansk [536]

Answer:

Explanation:

From, the given information: we are not given any value for the mass, the proportionality constant and the distance

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Let's recall that:

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Similarly, The equation of mption:

x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})

replacing our assumed values:

where v_=0 \ and \ g= 9.81

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1000.981 = 0.981 t

t = 1000.981/0.981

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