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3 years ago

What is the area of the object above?

Mathematics

2 answers:

Mariana [72]3 years ago

8 0

Answer:

Step-by-step explanation:

First, the object is a composite polygon. Its a shape with a bunch of shapes in it. This one has 2 rectangles in it.

One is 12x8, the other is 6x5.

To get the total area, you have to add the area of the smaller shapes.

(12x8)+(6x5)=area

12x8=96

6x5=30

96+30=126

area=126in^2

Ludmilka [50]3 years ago

3 0

C. 126 is the correct answer

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Plz answer thanks asap need it really bad

Kisachek [45]

I believe its C

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3 years ago

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Solve the following system of equations: −2x + y = 1 −4x + y = −1

Katyanochek1 [597]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}-2x+y=1\\-4x+y=-1&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=1\\4x-y=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it to the first equation:}\\\\-2(1)+y=1\\-2+y=1\qquad\text{add 2 to both sides}\\y=3$

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3 years ago

What ate the domain and range of f(x)(1/6)x+2?

never [62]

Answer:

Domain : all real numbers

Range: All numbers greater than 2

Step-by-step explanation:

The shark. (Haha, I'm sorry.)

There are no restrictions on the x. X can be any real number.

The range, however, does have restrictions. The range has to be a number greater than 0.

Why?

Because any number that you put in for x won't make the range less than 2. If you put in zero for x, the range is 2.

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3 years ago

Show all steps!!!

Lunna [17]

$-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3$
$\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}$
$\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}$
$=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}$
$=-\frac{53}{6}$

4 0

3 years ago

24. Use the intercepts to graph the equation.

romanna [79]

Answer:

See below ~

Step-by-step explanation:

<u>Finding x-intercept</u>

Take y = 0
2x - 5(0) = 10
2x = 10
x = 5
x-intercept is at (5, 0)

<u>Finding y-intercept</u>

Take x = 0
2(0) - 5y = 10
-5y = 10
y = -2
y-intercept is at (0, -2)

<u>Graph (with points marked)</u>

5 0

2 years ago

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