The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:

So, we have:

Evaluate

Hence, the equation of the hyperbola is 
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Answer: 1/5
Step-by-step explanation:
(1--1)/(4--6) = 2/10 = 1/5
The vertex of the given modulus function is (3,-7).
Given information:
The given modulus function is,

It is required to find the vertex of the given function.
<h3>What is the vertex of a modulus function?</h3>
Modulus function is in the shape of V. The notch of V is the vertex of the function.
The given function can be defined as,

From the above function, it can be concluded that the vertex of the function should be (3,-7). Also shown in the attached image.
See the attached image.
Therefore, the vertex of the given modulus function is (3,-7).
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Answer: A. $4.12
Step-by-step explanation:
Y=a(1+r/n)^nt is the equation we use to solve this.
a= $0.43
t=37 - take 1980 and subtract it from 2017
r= .063 - the 6.3% goes into a decimal
n = 1
Y= ?
Y= 0.43( 1+ .063/1) ^1*37
Y= 0.43 (1.063) ^37
Y= 4.12