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Levart [38]
2 years ago
5

What is the vertex of the graph of f(x) = |x 3| 7? (3, 7) (7, 3) (–3, 7) (7, –3).

Mathematics
2 answers:
KatRina [158]2 years ago
5 0

The vertex of the given modulus function is (3,-7).

Given information:

The given modulus function is,

f(x)=|x-3|-7

It is required to find the vertex of the given function.

<h3>What is the vertex of a modulus function?</h3>

Modulus function is in the shape of V. The notch of V is the vertex of the function.

The given function can be defined as,

f(x)=x-10;x\geq3\\&#10;f(x)=-x-4;x

From the above function, it can be concluded that the vertex of the function should be (3,-7). Also shown in the attached image.

See the attached image.

Therefore, the vertex of the given modulus function is (3,-7).

For more details about modulus function, refer to the link:

brainly.com/question/18793028

marshall27 [118]2 years ago
5 0

The vertex of the graph of f(x) is (-3, 7).

<h2>Given that</h2>

Graph; \rm  f(x) = |x + 3| + 7

<h3>We have to determine</h3>

What is the vertex of the graph of f(x)?

According to the question

The standard form of the absolute value function is;

\rm y = a|x-h|+k

Where h and k are the vertexes of the function.

Graph; \rm  f(x) = |x + 3| + 7

Converting the equation into the standard form the absolute value function;

\rm  f(X)=|x + 3| + 7\\&#10;\\&#10;f(x) = |x-(-3)|+7

On comparing with the standard absolute value function the vertices of the graph f(x).

h = -3 and k = 7

Hence, the vertex of the graph of f(x) is (-3, 7).

To know more about Absolute Function click the link given below.

brainly.com/question/1883473

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Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

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Using the characteristic equation:

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Therefore the zeros must come from the polynomial:

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Solving for \lambda:

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These roots give the next solutions:

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Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

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Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

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Evaluating    y(0)=2 :

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Evaluating     y'(0)=2 :

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Finally, the solution is given by:

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