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Paha777 [63]
3 years ago
14

I need helppp asap 7x+3=4x-9

Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0

Answer: -4

Step-by-step explanation: Hello! :) To get started we need to use the equation 7x+3=4x-9, First, we need to subtract 4x from both sides to get 3x+3=-9, then we need to subtract 3 on both sides to get 3x=-12, Finally, we need to divide both sides by 3 to get x = -4. So x = -4.

Hope this helps!

Please consider marking Brainliest I am 1 away from 50!

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Radda [10]
I’m pretty sure the answer is A I hope that helps :)
5 0
3 years ago
A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su
dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

<em>H</em>₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

<em>H</em>ₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a <em>t</em>-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }

Given:

\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86

Compute the value of the test statistic as follows:

t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70

Thus, the value of the test statistic is 4.70.

7 0
3 years ago
If k is the midpoint of LM and k (-4,-6) and m(-7,-3). find l (endpoint)​
Fudgin [204]

Answer:

(-1,-9) <u>PLEASE MARK BRAINLIEST!!!!!</u>

Step-by-step explanation:

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4 years ago
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Answer:

-\frac{5}{4}

Step-by-step explanation:

m=\frac{rise}{run}=\frac{-4-1}{1+3}=\frac{-5}{4} =-\frac{5}{4}

Hope this helps.

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Simplify 3.(9.).<br> A. 3x<br> B. 27x<br> C. 9x<br> D. 2 + 7x
grin007 [14]

i think your answer is B. 27x

6 0
3 years ago
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