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3 years ago

PLEASE HELP!!! ( I'll name you brainliest if you get it right)

Mathematics

1 answer:

aksik [14]3 years ago

3 0

Answer:

10(5+4)^/4

10(9)^/4

90^/4

=2025

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In a society there are 30 men and 20 women members.

krek1111 [17]

<h3>Answer: 2/5</h3>

This is because there are 20 women out of 50 people total (30+20 = 50).

So 20/50 = 2/5

This converts to the decimal form 0.4 and the percentage form 40%

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3 years ago

A recipe for cookies requires 2/3 cup of butter.Rama wants to make 3/4 of the recipe.How many cups of butter should Rana use to

makkiz [27]

3/4 x 2/3 = 6/12 = 1/2

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2 years ago

If yu were to randomly survey 500 people each from two largest us cities would this be a random study why or why not HELP NEEDED

Valentin [98]

Answer:

If you're timed then I would say,

Yes this is a random study because the problem specifically states that the survey samples were randomly selected from populations.

I think that is the answer! However, if you have time I would wait for another person to answer as well because I'm terrible at statistics :(

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2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students

xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample size $n_1$ = 178

the sample size $n_2$ = 226

the sample mean $\overline x_1$ = 54.4

the sample mean $\overline x_2$ = 74.5

population standard deviation $\sigma_1$ = 18.58

population standard deviation $\sigma_2$ = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for $Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005}$ is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = $Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}$

$1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}$

$1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}$

$1.645 \times\sqrt{2.34042}$

$\simeq$ 2.52

The lower limit = $( \overline x_1 - \overline x_2) - (M.O.E)$

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = $( \overline x_1 - \overline x_2) + (M.O.E)$

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

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3 years ago

The GCF of 6x^2y−24x^3+18xy^4 is

finlep [7]

Answer:

Step-by-step explanation:

All of the variables are divisible by 6.

7 0

2 years ago