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Makovka662 [10]
3 years ago
5

What is the result when the number 86 is decreased by 9%?

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
78.26

Hope this helps!!!
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For the following right triangle, find the side length x.​
never [62]

Answer:

x = 10

Explanation:

Using Pythagoras Theorem:

  • a² + b² = c²

Solve:

8² + 6² = x²

x² = 64 + 36

x² = 100

x = √100

x = 10

8 0
2 years ago
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What is the range of f(x)=x^3
Alecsey [184]
Infinity because it's a cubic function with no restricted range or domain
3 0
2 years ago
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Find what x =_______​
kramer

Answer:

x=18

Step-by-step explanation:

ok, so you mulityply base and hieght then divide by 2

your base is 6 and your height is 6

6x6=36

36/2=18

your welcome

7 0
3 years ago
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198 sq.yd. 8 sq. ft. x 7 =
vichka [17]

Answer:

Step-by-step explanation:

Give the data

198 sq.yd × 8 sq ft ×7

Note that we have two unit of measurement which are yd and ft and 7 is just a constant

So we need to convert them,

Then, 1 yd = 3ft

Also notice that they are square.

Then square both sides of the comparison

(1 yd)² = (3 ft)²

1 sq.yd = 9 sq.ft

Then, back to our question,

198 sq.yd × 8 sq ft ×7

Let covert to ft

198 sq.yd× (9 sq.ft/1 sq.yd) ×8 sq.ft×7

sq.yd cancels out

99,792 sq.ft × sq.ft

99,792 ft⁴

Let convert to yd

198 sq.yd × 8 sq ft ×7

198 sq.yd×8 sq.ft (1 sq.yd / 9sq.ft )×7

1,232 sq.yd × sq.yd

1,232 yd⁴

4 0
3 years ago
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There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level
aliya0001 [1]

Answer:

d =  787.81cm^3

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

r=4cm --- radius

h = 13cm --- height

The volume is calculated as:

Volume = \frac{1}{3} \pi r^2h

So, we have:

V_1 = \frac{1}{3} \pi * 4^2 * 13

V_1 = \frac{208}{3} \pi

The snow cone in a cup has the following dimension

Shape: Cylinder

r=8cm --- radius

h = 5cm --- height

The volume is calculated as:

Volume =  \pi r^2h

So, we have:

V_2 =  \pi *8^2 * 5

V_2 =  \pi *320

V_2 =  320\pi

The difference (d) in the amount they hold is:

d = V_2 - V_1

d = 320\pi - \frac{208\pi}{3}

Take LCM

d =  \frac{3*320\pi -208\pi}{3}

d =  \frac{960\pi -208\pi}{3}

d =  \frac{752\pi}{3}

Take \pi = 22/7

d =  \frac{752}{3} * \frac{22}{7}

d =  \frac{752 * 22}{3*7}

d =  \frac{16544}{21}

d =  787.81cm^3

4 0
3 years ago
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