Question

2(4x - 1) < 4(3x+1), where x ∈ {set of all negative Integers}​

Answer 1

$\large\underline{\sf{Solution-}}$

Given inequation:

$\sf 2(4x-1)$

$\sf\longmapsto 8x-2$

$\sf\longmapsto 8x-2-4$

$\sf\longmapsto 8x-6$

$\sf\longmapsto 8x-6-8x$

$\sf\longmapsto -6$

$\sf\longmapsto 4x>-6$

$\sf\longmapsto \dfrac{4x}{4}>\dfrac{-6}{4}$

$\sf\longmapsto x >-1\dfrac{1}{2}$

Therefore:

$\sf\longmapsto\boxed{ x=\{-1\}}\ \ Ans.$