Answer:
Step-by-step explanation:
We choose arbitrary values for x and in each case calculate y = 2x + 5.
If x = 0, y = 5; if x = 3, y = 11, and so on.
How? when x = 3, y = 2(3) + 5 = 6 + 5 = 11.
The table, with rows and columns suitable to this problem, would look like:
x y
0 5
3 11
10 25
and so on
c. 11
it's c because if they start with 5 then
1=5
2=6
3=7
4=8
5=9
6=10
7=11
Answer:
No, it is not a function because one of the x values have two different y values
If you could post the picture I can help
Answer:
112 PIE CM CUBE
Step-by-step explanation:
