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andreev551 [17]
3 years ago
7

Is x-8 a factor of p(x)= x3-9x2+12x-17

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

x-8 is not a factor of p(x) = x^3-9x^2+12x-17

Step-by-step explanation:

In order to check whether a term is factor of given expression or not we put the value in the expression. If the expression is zero, then the value is a factor otherwise not.

Given polynomial is:

p(x) = x^3-9x^2+12x-17

We have to check if x-8 is factor of given polynomial or not. for that purpose we have to put

x-8 = 0\\x = 8

Putting in the polynomial

p(x) = (8)^3 - 9(8)^2+12(8)-17\\= 512 - 8(64) + 96 - 17\\= 512-512+96-17\\=79

Hence,

x-8 is not a factor of p(x) = x^3-9x^2+12x-17

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/2367554
  • brainly.com/question/2670657

#LearnwithBrainly

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