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andreev551 [17]
3 years ago
7

Is x-8 a factor of p(x)= x3-9x2+12x-17

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

x-8 is not a factor of p(x) = x^3-9x^2+12x-17

Step-by-step explanation:

In order to check whether a term is factor of given expression or not we put the value in the expression. If the expression is zero, then the value is a factor otherwise not.

Given polynomial is:

p(x) = x^3-9x^2+12x-17

We have to check if x-8 is factor of given polynomial or not. for that purpose we have to put

x-8 = 0\\x = 8

Putting in the polynomial

p(x) = (8)^3 - 9(8)^2+12(8)-17\\= 512 - 8(64) + 96 - 17\\= 512-512+96-17\\=79

Hence,

x-8 is not a factor of p(x) = x^3-9x^2+12x-17

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/2367554
  • brainly.com/question/2670657

#LearnwithBrainly

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Please answer this correctly
ArbitrLikvidat [17]

Answer:

326

Step-by-step explanation:

l x w

7x8

25x6

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326

3 0
3 years ago
Kevin runs a farm stand that sells apples and raspberries. Each pound of apples sells for $3.50 and each pound of raspberries se
krek1111 [17]

Kevin sold 10 pounds of apples and 20 pounds of raspberries.

Step-by-step explanation:

Given,

Cost per pound of apples = $3.50

Cost per pound of raspberries = $4

Total amount earned = $115

Let,

x represent the pounds of apples sold

y represent the pounds of raspberries sold

According to given statement;

3.50x+4y=115     Eqn 1

y = 2x                  Eqn 2

Putting value of y from Eqn 2 in Eqn 1

3.50x+4(2x)=115\\3.50x+8x=115\\11.50x=115

Dividing both sides by 11.50

\frac{11.50x}{11.50}=\frac{115}{11.50}\\x=10

Putting x=10 in Eqn 2

y=2(10)\\y=20

Kevin sold 10 pounds of apples and 20 pounds of raspberries.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/4279146
  • brainly.com/question/4354581

#LearnwithBrainly

5 0
3 years ago
The point A (5,11) is reflected across the x-axis. How long is the segment AA'?<br>​
Nikitich [7]

Answer:  The required length of the segment AA' is 11 units.

Step-by-step explanation:  Given that the point A(5, 11) is reflected across the X-axis.

We are to find the length of the segment AA'.

We know that

if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).

So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).

Now, we have the following distance formula :

The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

PQ=\sqrt{(c-a)^2+(d-b)^2}.

Therefore, the length of the segment AA' is given by

AA'=\sqrt{(5-5)^2+(-11-11)^2}=\sqrt{11^2}=11.

Thus, the required length of the segment AA' is 11 units.

7 0
3 years ago
(115) the product of integers x, y, and z is even. is z even?
djyliett [7]
1. X/Y = Z

if x = 6, y = 2, then z = 3, not even

if x = 6, y = 3, then z = 2, even

<span>2. Z=XY </span>

so (z)^2 = 2*k (because x*y*z = 2k, where k is an integer)

<span>Sufficient, as if square of an integer is even ,then the integer is even</span>
5 0
3 years ago
Tiffany, Lori, and Mika are practicing for an egg-toss contest. The distance from Tiffany to Lori is 17 inches. The distance fro
Sloan [31]
If you add all of the numbers together the answer your going to get is 17+32+28 which equals 77
5 0
3 years ago
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