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2 years ago

Is x-8 a factor of p(x)= x3-9x2+12x-17

Mathematics

1 answer:

BartSMP [9]2 years ago

8 0

x-8 is not a factor of $p(x) = x^3-9x^2+12x-17$

Step-by-step explanation:

In order to check whether a term is factor of given expression or not we put the value in the expression. If the expression is zero, then the value is a factor otherwise not.

Given polynomial is:

$p(x) = x^3-9x^2+12x-17$

We have to check if x-8 is factor of given polynomial or not. for that purpose we have to put

$x-8 = 0\\x = 8$

Putting in the polynomial

$p(x) = (8)^3 - 9(8)^2+12(8)-17\\= 512 - 8(64) + 96 - 17\\= 512-512+96-17\\=79$

Hence,

x-8 is not a factor of $p(x) = x^3-9x^2+12x-17$

Keywords: Polynomials, expressions

Learn more about polynomials at:

#LearnwithBrainly

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Step-by-step explanation:

From the question we are told that:

Dimension of ABC

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