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prohojiy [21]
3 years ago
9

Can someone Graph y = x + 4

Mathematics
1 answer:
Alja [10]3 years ago
7 0
Use desmos it could probably help you.
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Morgan is making two cookie recipes. Recipe A calls for one-third less than twice the number of cups of sugar that Recipe B call
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morgan dropped the sugar and has to go to the store to get more skip the question.

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3 years ago
April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R&B CDs. What is t
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The answer is B: <span>choosing five CDs where not all of them are pop</span>
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Pablo's retirement party will cost $8 if he invites 4 guests. If there are 6 guests, how
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$12

Step-by-step explanation:

Step 1:

$8 : 4 = x : 6

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Hope This Helps :)

6 0
3 years ago
-6x - 2x = 40. Calculate and show work
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-6x-2x= 40
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3 years ago
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The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
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