Dennis has jus made the final monthly payment necessary for paying off his car financing
1 answer:
You might be interested in
Hello,
1) Conditions:
x+2>=0==>x>-2
x>=0
So x>=0
1/5 ln(x+2)^5 +1/2 [ln x -ln(x^2+3x+2)^2]
=ln(x+2)+ ln√x - ln(x+1)(x+2)
1) Conditions:
x+2>=0==>x>-2
x>=0
So x>=0
1/5 ln(x+2)^5 +1/2 [ln x -ln(x^2+3x+2)^2]
=ln(x+2)+ ln√x - ln(x+1)(x+2)