Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer:
72 m^2
Step-by-step explanation:
Perimeter = 36
Length + width = 18
w + w + 6 = 18
2w + 6 = 18
2w = 12
w = 6
Length + 6 = 18
Length = 12
Area = 6 * 12 = 72 m^2
Answer and Step-by-step explanation:
Distribute the 6mn to the 2m and -3n
The answer is:
#teamtrees #WAP (Water And Plant)
Answer:
4n=c
Step-by-step explanation: i took the quiz if this is wrong its prob a differnt
quiz the last person i answered got md at befor i didnt know what quiz she take a.
Answer:
48
Step-by-step explanation:
