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Digiron [165]
3 years ago
14

{WORTH BRAINLIEST WITH AN EXPLANATION} Janine is a police officer patrolling a street. She drives 2.2 km east, then 4.4 km west,

then 1.7 km east. If east is the positive direction, which of the following equations are accurate? (select all that apply)

Physics
1 answer:
icang [17]3 years ago
5 0

Answer:

Options (3) and (6)

Explanation:

Janine drives 2.2 km East.

Since, distances measured in the East are positive,

Displacement = 2.2 km

Then she drives 4.4 km west

Displacement = -4.4 km

Followed by 1.7 km in the East

Displacement = 1.7 km

Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km

\overrightarrow{d}=-0.5 km

Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km

d = 8.3 km

Therefore, Options (3) and (6) will be the answer.

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The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

x=V_{o}cos \theta t----------------------(1)

y=y_{o}+V_{o} sin \theta t - \frac{1}{2}gt^{2}---------(2)

V=V_{o}-gt ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

V_{o} is the golf ball's initial velocity

\theta=0\° is the angle (it was  a horizontal shot)

t is the time

y is the final height of the ball

y_{o} is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

t=\sqrt{\frac{2 y_{o}}{g}}

t=\sqrt{\frac{2 (12.5 m)}{9.8 m/s^{2}}}

t=1.597s

Substituting (6) in (1):

67.1 =V_{o} cos(0\°) 1.597-------------------(4)

Step 2:  Finding V_{o}:

From equation(4)

67.1 =V_{o}(1) 1.597

V_0 = \frac{6.71}{1.597}

V_{o}=42.01 m/s (8)  

Substituting V_{o} in (3):

V=42.01 -(9.8)(1.597)

v =42 .01 - 15.3566  

V=26.359 m/s

5 0
3 years ago
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