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vesna_86 [32]
3 years ago
14

A car accelerates from rest at 4 m/s^2. What is the velocity of the car after 4 seconds?

Physics
1 answer:
IRISSAK [1]3 years ago
5 0
8 i believe is the correct answer
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You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip take
valkas [14]

Answer: 2 hr 45 min

Explanation:

Given

The average speed between San Diego and Los Angeles is 105\ kmph

time taken for this trip is  1\ hr\ 50\ min\ or\ \frac{11}{6}\ hr

Distance between San Diego and Los Angeles is

\Rightarrow d=105\times \dfrac{11}{6}\\\\\Rightarrow d=192.5\ km

For Friday afternoon, the average speed is  70\ km/h

time taken to complete the trip is

\Rightarrow t=\dfrac{192.5}{70}\\\\\Rightarrow t=2.75\ hr\ or\ 2\ hr\ 45\ min

3 0
3 years ago
Imagine a landing craft approaching the surface of Callisto, one of Jupiter's moons. If the engine provides an upward force (thr
nordsb [41]

Answer:

W=3456 N

Explanation:

Force 1 F_1=3456

Force 2 F_2=2333N

Acceleration at stage 2 a_2=0.39

Generally the weight of the Craft W is given as

W= upward force(thrust)

Therefore

W=3456 N

5 0
3 years ago
What disagrees with laplace hypothesis of the suns formation
slega [8]

Answer:

The sun's mass moved toward the outer edge of it

Explanation:

3 0
3 years ago
Sunlight has its maximum intensity at a wavelength of 4.83 x 10'm; wha energy does this correspond to in e?
Lera25 [3.4K]

Answer:

E = 2,575 eV

Explanation:

For this exercise we will use the Planck equation and the relationship of the speed of light with the frequency and wavelength

     E = h f

     c = λ f

Where the Planck constant has a value of 6.63 10⁻³⁴ J s

Let's replace

    E = h c / λ

Let's calculate for wavelengths

    λ = 4.83 10-7 m     (blue)

    E = 6.63 10⁻³⁴ 3 10⁸ / 4.83 10⁻⁷

    E = 4.12 10-19 J

The transformation from J to eV is 1 eV = 1.6 10⁻¹⁹ J

    E = 4.12 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

    E = 2,575 eV

5 0
4 years ago
a train traveling at 30m/s comes to a complete stop in 20 sec.how far did the train go during the deceleration
elixir [45]

Answer:

600m

Explanation:

v=30m/s

t=20s

s=VT

20×30=600m

3 0
3 years ago
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