Answer: 170km/hr to the South
Explanation:
The resultant velocity of the plane ilwill be gotten by adding the value of the velocities of the plane with the tallwind. It should be noted that the direction of the wind is.takwn into consideration.
Therefore, the resultant velocity of the plane will be:
= 20km/hr + 150km/hr
= 170km/hr to the South
Answer:
The tension in string P is 25 N, while that of Q is 85 N.
Explanation:
Considering the conditions for equilibrium,
i. Total upward force = Total downward force
+
= 110 N
ii. Taking moment about P,
clockwise moment = anticlockwise moment
110 × (2.5 - 0.8) =
× (3 - 0.8)
110 × 1.7 =
× 2.2
187 = 2.2
= 
= 85 N
From the first condition,
+
= 110 N
+ 85 N = 110 N
= 110 - 85
25 N
Therefore, the tension in string P is 25 N while that of Q is 85 N.
Top left: The slope of the line gives the (constant) acceleration of the moving object because the plot describes the velocity of some moving object. It's hard to tell what points the line passes through in the picture you took, but whatever slope/acceleration you find, that value will stay the same regardless of the time.
Top middle: The slope of the line is negative, which means acceleration has a negative sign. And because the line describes velocity over time, the fact that velocity is linear means that acceleration is constant.
Top right: The acceleration is the slope of the tangent line to the parabola at
. You can visually confirm that the slope of this line would be positive. Now, the average velocity between
and
is

Judging by the plot,
seems like a pretty reasonable choice among the answers.
Bottom left: The slope of the tangent line at any point on the plot would be negative. Because velocity is non-linear,
will not be constant.
Bottom middle: Opposite situation as in [bottom left].
Bottom right: The acceleration can only be negative for
, which means
must be the correct answer.
Answer:
Net flow rate = 0.00035 m³/s
Explanation:
The speed of plate 1, U₁ = 5 m/s
The speed of plate 2, U₂ = 1.5 m/s
The two plates are moving in different directions, the net speed will be gotten by taking the difference of the average of the two plates
The average speed due to the movement of plate 1 = U₁/2 = 5/2 = 2.5 m/s
The average speed due to the movement of plate 2 = U₂/2 = 1.5/2
= 0.75 m/s
The net average speed of the fluid= U₁/2 - U₂/2
The net average speed of the fluid = 2.5 - 0.75 = 1.75 m/s
Net flow rate = Net average speed * Area of the plate
Width of the plate, v = 5 cm = 0.05 m
Distance between the plates = 4 mm = 0.004 m
Area = 0.05 * 0.004
Area = 0.0002 m²
Net flow rate = 1.75 * 0.0002
Net flow rate = 0.00035 m³/s