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lisabon 2012 [21]
3 years ago
15

I need help fast please

Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

triangle, circle

Step-by-step explanation:

I put a link at the bottom to show you how i got my answer

The vertical cross-section of a cone is a triangle. The horizontal cross-section is a circle

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Please Solve The Triangle for x
telo118 [61]
What triangle? Is there one on here?
4 0
2 years ago
Find the area please
tatuchka [14]

Answer:

D

Step-by-step explanation:

Recall that the area of a triangle is given by:

\displaystyle A = \frac{1}{2} bh

In this case, the base is <em>x</em> and the height is <em>y</em>. Hence:

\displaystyle A = \frac{1}{2} xy

We can write the following ratios:

\displaystyle \sin \alpha = \frac{x}{12} \text{ and } \cos \alpha = \frac{y}{12}

Solve for <em>x</em> and <em>y</em>:

\displaystyle x = 12\sin \alpha \text{ and } y = 12\cos \alpha

Substitute:

\displaystyle A = \frac{1}{2}\left(12\sin \alpha\right)\left(12\cos \alpha\right)

And simplify. Hence:

\displaystyle A = 72\sin \alpha \cos\alpha

In conclusion, our answer is D.

6 0
3 years ago
NEED HELP ASAP PLEASE WITH EXPLANATION PLEASE
KonstantinChe [14]

Answer:

(1) 20%

Step-by-step explanation:

→ Find the difference in price

200 - 160 = 40

→ Divide difference by original price

40 ÷ 200 = 0.2

→ Multiply the answer by 100

0.2 × 100 = 20%

7 0
3 years ago
A helicopter is flying above a town. the local high school is directly to the east of the helicopter at a 20° angle of depressio
guapka [62]
Answer: 4.5 miles

Explanation:

When you draw the situation you find two triangles.

1) Triangle to the east of the helicopter

a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°

b) hypotensue = distance between the high school and the helicopter

c) opposite-leg to angle 20° = heigth of the helicopter

d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x

2) triangle to the west of the helicopter

a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°

b)  distance between the helicopter and the elementary school = hypotenuse

c) opposite-leg to angle 62° = height of the helicopter

d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x

3) tangent ratios

a) triangle with the helicpoter and the high school

tan 20° = Height / x ⇒ height = x tan 20°

b) triangle with the helicopter and the elementary school

tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°

c) equal the height from both triangles:

x tan 20° = (5 - x) tan 62°

x tan 20° = 5 tan 62° - x tan 62°

x tan 20° + x tan 62° = 5 tan 62°

x  (tan 20° + tan 62°) = 5 tan 62°

⇒ x = 5 tant 62° / ( tan 20° + tan 62°)

⇒ x = 4,19 miles

=> height = x tan 20° = 4,19 tan 20° = 1,525 miles

4) Calculate the hypotenuse of this triangle:

hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²

hipotenuse = 4.46 miles

Rounded to the nearest tenth = 4.5 miles

That is the distance between the helicopter and the high school.
5 0
3 years ago
Read 2 more answers
If 4x^2-100=0 the roots of the equation are
Marrrta [24]

Your equation:                   4x² - 100           =  0

Factor the left side:      (2x + 10) · (2x - 10) = 0

This equation is true if either factor is zero.

-- One factor:                     2x + 10 = 0
  
Divide each side by 2:            x + 5 = 0
Subtract 5 from each side:      x      = -5 .


-- The other factor:               2x - 10  =  0

Divide each side by 2:            x + 5 = 0
Add  5  to each side:              x      =  5 .

8 0
3 years ago
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