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DochEvi [55]
3 years ago
11

P.7 Is an even number or Q: 3 is square root of 10 ( P v Q )answer asap please

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0
The correct answer is the Last Choice ft equals truth
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21) Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the
diamong [38]

Answer:

Step-by-step explanation:

Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the

race at 10 kmph. If his total time for the entire race was 1.74 hours, how far did he run in

the first part of the race?

First part :

Total Distance = 12 km

First part Speed = 8kmph

Let distance covered on first part = x

Second part speed = 10kmhr

(8*x)

6 0
3 years ago
In a large data set the 40th percentile is 125 and the 82nd percentile is 158. Approximately what percentage of observations lie
liq [111]

Answer:

42% of observations lie between 125 and 158.

Step-by-step explanation:

Interpretation of a percentile

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

Two values have a percentile, how many are between then?

In this example, y is larger than x.

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

When a value Z is said to be in the yth percentile of a set, y% of the values in the set are lower than V and (100-y)% of the values in the set are higher than V.

Also, (y-x)% of the values are between V and Z.

In this problem, we have that:

125 is the 40th percentile

158 is the 82nd percentile

Approximately what percentage of observations lie between 125 and 158

82 - 40 = 42% of observations lie between 125 and 158.

3 0
3 years ago
Help I’ll give Brainly
Temka [501]

Answer:

probability = area of shaded region / total area

P = π (y²-x²) /πy²

P = y²-x²/y²

Option D is correct ...

mark me as brainliest ❤️

3 0
3 years ago
Intrigued by a 2013 study at the University of Nebraska that suggested marijuana smokers may be thinner than other adults, a gro
Reptile [31]

this question is incomplete, the complete question is:

1. is this model effective

2. what is the correlation coefficient for this data.

3. for a student with a bmi of 25, what is the predicted number of hours under the influence.

Step-by-step explanation:

1. first of all this model is not effective because we have r² as 0.134. this tells us that only 13.4 percent of the of the variations that exist in this data has been explained by the model

1. we get the correlation coefficient by

+-\sqrt{r^{2} }

the regression slope coefficient has a negative sign. this is what we would use in calculating the correlation coefficient.

-\sqrt{r^{2} }

= -√0.134

= -0.366

therefore the correlation coefficient is -0.366

2. to get the number of hours under the influence with a bmi of 25

the equation is

49.2-1.15bmi

= 49.2-1.15(25)

= 49.2-28.75

= 20.45

8 0
3 years ago
What is the simplified form of the following expression? Assume y=0 ^3 sqrt 12x^2/16y
pochemuha

For this case we must simplify the following expression:

\sqrt [3] {\frac {12x ^ 2} {16y}}

We rewrite the expression as:

\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=

We multiply the numerator and denominator by:

(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=

We use the rule of powera ^ n * a ^ m = a ^ {n + m} in the denominator:

\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=

Move the exponent within the radical:

\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=

\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=

\frac{\sqrt[3]{6x^2*y^2}}{2y}

Answer:

\frac{\sqrt[3]{6x^2*y^2}}{2y}

7 0
3 years ago
Read 2 more answers
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