We have that
(w^5*z^2)*(-9*w^2*z^<span><span>5)</span>
</span><span>Multiplying exponential expressions
we know that
</span>w^5<span> multiplied by </span>w^<span>2 = w</span>^<span>(5 + 2) = w</span>^7
and
z^2<span> multiplied by </span>z^<span>5 = z</span>^<span>(2 + 5) = z</span>^7
therefore
(w^5*z^2)*(-9*w^2*z^5) =-9*( w^7)*( z^7)
-9*( w^7)*( z^7)=-(3^2)*( w^7)*( z^7)
the answer is
-(3^2)*( w^7)*( z^7
Answer:
The answer to this question is gotta be 0
Step-by-step explanation:
Because a normal distribution gives an area between 0 and z and the area for P(X=46) = 0
Santosh's cousin is 15 years old because 49-4=45. Divide 45 by 3 and the quotient is 15. To check: 15 times 3= 45. Add 4 and the sum is 49.
Sorry i can’t quite see the image can you do another one
